date ：从下个月的第 2 天到第 1 天按月分组答案

【问题标题】：date : group by month from day 2 to day 1 next monthdate ：从下个月的第 2 天到第 1 天按月分组
【发布时间】：2012-04-03 20:48:50
【问题描述】：

我有这样的查询：

SELECT EXTRACT(MONTH FROM d.mydate) AS synmonth, SUM(apcp) AS apcptot
FROM t_synop_data2 d
WHERE d.mydate
BETWEEN '2011-01-01' AND '2011-12-31' 
AND d.idx_synop = '06712'
GROUP BY synmonth

此查询添加一个月内的所有降雨 (apcp)，如下所示：

1   32.8  => from 2011.01.01 to 2011.01.31
2   27.2 => from 2011.02.01 to 2011.02.28
3   21.0
4   21.8
5   88.5
6   131.4
7   118.6
8   57.1
9   80.9
10  84.6
11  1.1
12  143.5 => from 2011.12.01 to 2011.12.31

这就是我想要的，但有一点不同。

这个区别是我必须从当月的第 2 天到下个月的第 1 天添加 apcp，然后返回类似上面的结果。

1   132.8 => from 2011.01.02 to 2011.02.01
2   27.2  => from 2011.02.02 to 2011.03.01
3   21.0
4   21.8
5   88.5
6   131.4
7   118.6
8   57.1
9   80.9
10  84.6
11  1.1
12  143.5 => from 2011.12.02 to 2012.01.01

我用 add_date()、extract() 或 date_format() 尝试了一些东西，但没有结果。

感谢您的回答文斯

【问题讨论】：

标签： mysql date group-by

【解决方案1】：

这里是查询：

SELECT EXTRACT(MONTH FROM ADDDATE(d.mydate,-1) ) AS synmonth
, SUM(apcp) AS apcptot
FROM t_synop_data2 AS d
WHERE ADDDATE(d.mydate,-1) BETWEEN '2011-01-01' AND '2012-12-31'
AND d.idx_synop = '06712'
GROUP BY synmonth

您可以像这样添加两列来检查结果：

SELECT EXTRACT(MONTH FROM ADDDATE(d.mydate,-1) ) AS synmonth
, SUM(apcp) AS apcptot
, MIN(d.mydate) AS date_min
, MAX(d.mydate) AS date_max
FROM t_synop_data2 AS d
WHERE ADDDATE(d.mydate,-1) BETWEEN '2011-01-01' AND '2012-12-31'
AND d.idx_synop = '06712'
GROUP BY synmonth

【讨论】：

【解决方案2】：

您可以按EXTRACT(MONTH FROM d.mydate - INTERVAL 1 DAY)分组

SELECT EXTRACT(MONTH FROM d.mydate) AS synmonth, SUM(apcp) AS apcptot
FROM t_synop_data2 d
WHERE d.mydate
BETWEEN '2011-01-01' AND '2011-12-31' 
AND d.idx_synop = '06712'
GROUP BY EXTRACT(MONTH FROM d.mydate - INTERVAL 1 DAY)

【讨论】：