【问题标题】:Passing an unsigned char array by reference in C++在 C++ 中通过引用传递无符号字符数组
【发布时间】:2013-10-26 19:08:41
【问题描述】:

全部!我在实施蛇密码的学校项目中遇到了一些困难。问题出在函数中

setKey(unsigned char (&user_key[32]))

我想将一个大小为 32 的字节数组传递给我的函数,然后让我的函数对该数组的值执行各种操作。我打印的代码无法编译,因为我收到错误 -

no known conversion for argument 1 from ‘unsigned char (*)[32]’ to 
‘unsigned char (&)   [32]’

我浏览了许多类似的帖子,但我发现的解决方案似乎都没有导致我的代码编译,或者如果它编译,则执行我想要的操作。不幸的是,我不记得我上次是如何编译代码的,但是当我编译时,在函数 setKey() 中打印出 user_key[] 的值给了我以下输出:

19, 0, 0, 0, 51, 0, 0, 0, 83, 0, 0, 0, 115, 0, 0, 0, 20, 0, 0, 0, 52, 0, 0, 0,
84, 0, 0, 0, 116, 0, 0, 0  

另外,当它运行时,它在打印出该行后以段错误退出 “这就是结束。我唯一的朋友,结束。”以及“检测到堆栈粉碎”警告。简而言之,我的代码似乎有各种各样的错误。任何帮助将不胜感激!

#include <iostream>
#include <math.h>

using namespace std;

class KeySchedule{

  int ip[64];
  int key_size;
  unsigned long long int k0;
  unsigned long long int k1;
  unsigned long long int k2;
  unsigned long long int k3;

public:

  KeySchedule(){

    /*The initial permutation. To be applied to the plaintext and keys.
      ip = {0, 32, 64, 96, 1, 33, 65, 97, 2, 34, 66, 98, 3, 35, 67, 99,
      4, 36, 68, 100, 5, 37, 69, 101, 6, 38, 70, 102, 7, 39, 71, 103,
      8, 40, 72, 104, 9, 41, 73, 105, 10, 42, 74, 106, 11, 43, 75, 107,
      12, 44, 76, 108, 13, 45, 77, 109, 14, 46, 78, 110, 15, 47, 79, 111,
      16, 48, 80, 112, 17, 49, 81, 113, 18, 50, 82, 114, 19, 51, 83, 115,
      20, 52, 84, 116, 21, 53, 85, 117, 22, 54, 86, 118, 23, 55, 87, 119,
      24, 56, 88, 120, 25, 57, 89, 121, 26, 58, 90, 122, 27, 59, 91, 123,
      28, 60, 92, 124, 29, 61, 93, 125, 30, 62, 94, 126, 31, 63, 95, 127};
    */

    for (int i = 0; i < 127; i++ ){
      ip[i] = (32*i) % 127;
    } 
    ip[127] = 127;

    k3 = 0; 
    k2 = 0; 
    k1 = 0;
    k0 = 0;  
    key_size = -1;
  }

  void setKey (unsigned char (&user_key)[32]){

    for (int i = 0; i<32; i++){
      cout << (int)(user_key)[i] << endl;
    }

    for (int i = 0; i<8; i++){
      k3 ^= (int)(user_key)[i] << (8-i);
      k2 ^= (int)(user_key)[i+8] << (8-i);
      k1 ^= (int)(user_key)[i+16] << (8-i);
      k0 ^= (int)(user_key)[i+24] << (8-i);
    }

  }
};

int main(){

   unsigned char testkey[]= {0x01, 0x02, 0x03, 0x04, 
                 0x05, 0x06, 0x07, 0x08, 
                 0x09, 0x0a, 0x0b, 0x0c, 
                 0x0d, 0x0e, 0x0f, 0x10,
                 0x20, 0x30, 0x40, 0x50, 
                 0x60, 0x70, 0x80, 0x90, 
                 0xa0, 0xb0, 0xc0, 0xd0, 
                 0xe0, 0xf0, 0x00, 0xff};

   cout << "The size of testkey is: " 
        << sizeof(testkey)/sizeof(*testkey) << endl;

   KeySchedule ks = KeySchedule();

   ks.setKey(&testkey);
   cout << "This is the end. My only friend, the end." << endl;
};

【问题讨论】:

    标签: c++ arrays pass-by-reference


    【解决方案1】:

    您正在传递unsigned char 数组的地址,即指向unsigned char[32] 的指针。你需要这个:

    ks.setKey(testkey);
    

    【讨论】:

    • 非常感谢您的帮助!但是,现在我在打印 user_key 的值时遇到了同样的问题。知道为什么要为数组的值打印 19, 0, 0, 0, 51, 0, 0, 0, ... 吗?
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