TypeError：采用一个位置参数，但给出了五个 [关闭]

Question

def double_preceding(values):

    '''(list of ints)->None

    Update each value in a list with twice
    the preceding value, and the first item
    with 0.

    For example, if x has the value
    [1,2,3,4,5], after calling the
    double_preceding with argument x,
    x would have the value[0,2,4,6,8]

    >>>double_preceding(2,3,4,5,6)
    [0,4,6,8,10]
    >>>double_preceding(3,1,8,.5,10)
    [0,6,2,16,1] 
    '''
    if values != []:
        temp = values[0]
        values[0] = 0
        for i in range(0, len(values)):
            double = 2 * temp
            temp = values[i]
            values[i] = double
    return #None

那我做错了什么？我在任何地方都没有发现问题，我已经尝试修复了一个小时。

我修复了代码：

def double_preceding(values):

    if values != 0:  
            temp = values[0]
            values[0] = 0
         for i in range(1, len(values)):
               double = 2 * temp
               temp = values[i]
               values[i] = double
    print(values)
    return#None

Answer 1

您的函数只接受一个参数，而您将 5 传递给它。替换：

>>>double_preceding(2,3,4,5,6)
[0,4,6,8,10]
>>>double_preceding(3,1,8,.5,10)
[0,6,2,16,1] 

与：

>>>double_preceding([2,3,4,5,6])
[0,4,6,8,10]
>>>double_preceding([3,1,8,.5,10])
[0,6,2,16,1] 

Answer 2

我很好奇您为什么决定传入列表的文字值而不是传递包含列表的变量。例如。

x = [1, 2, 3, 4, 5]

double_preceding(x)

如果你只是传递它 x 取决于你在函数中的代码，你的函数应该可以工作。您可以发布函数内部的实际代码吗？