从特定文件路径、相对路径、Unix 可执行文件打开 Blender（程序）

Question

在我之前的问题Open a file from a specific program from python 中，我发现了如何使用子进程来打开一个程序（Blender）——嗯​​，一个特定的.blend 文件——从带有此代码的特定文件路径。

import os
import subprocess

path = os.getcwd()
os.system("cd path/")
subprocess.check_call(["open", "-a", os.path.join(path, "blender.app"),"Import_mhx.blend"])

对于the help of a guy at a forum，我想在.blend 文件中使用相对路径，所以我以这种方式更改了代码（适用于Windows）

import os
import subprocess

# This should be the full path to your Blender executable.
blenderPath = "/cygdrive/c/Program Files/Blender Foundation/blender-2.62-release-windows32/blender.exe"

# This is the directory that you want to be your "current" directory when Blender starts
path1 = "/Users/user/Desktop/scenario/Blender"

# This makes makes it so your script is currently based at "path1"
os.chdir(path1)

subprocess.check_call([blenderPath, "Import_mhx.blend"])

对于 Mac，

import os
import subprocess

path = os.getcwd()
os.system("cd path/")
print (path)
# This should be the full path to your Blender executable.
blenderPath = path + "/blender.app/Contents/macos/blender"

# This is the directory that you want to be your "current" directory when Blender starts
path1 = "/Users/user/Desktop/scenario/Blender"

# This makes makes it so your script is currently based at "path1"
os.chdir(path1)

subprocess.check_call([blenderPath, "Import_mhx.blend"])

结果：

1. 在 Windows 中，它可以正常工作。
2. 在 Mac 上，结果是文件已打开，但程序似乎没有打开。我觉得这很奇怪。

问题：

1. 我应该为搅拌机（UNIX 可执行文件）放置任何扩展名以使其打开吗？
2. 有没有其他方法可以让我正确打开程序，同时还能使用.blend 文件中的相对路径？

Answer 1

import os
import subprocess

blenderPath = "./blender.app/Contents/MacOS/blender"

path1 = "./"

os.chdir(path1)

subprocess.check_call([ blenderPath, "Animation.blend"])

两个搅拌器都可以完美打开，.blend 文件中的相对路径可以正常工作:)