NodeJs POST请求不起作用

Question

假设我有一个网址

https://someAPI.com/authorize?x=val1&y=val2

其中 x 和 y 是我发送的有效负载值 我怎样才能以这种方式进行发布请求？

我试过这个：

var https = require('https')

var options = {
    url: 'https://someAPI.com/authorize?x=val1&y=val2',
    method: 'POST',
    headers: {
         ....
    }
}

https.request(options, function(res) {
    var str = ""
    res.on('data', function(data){
        str+=data
    })
    res.on('end', function() {
        console.log(str)
    })
})

我没有得到任何回报。我做错了什么？

编辑：这是我认为的格式：

REQUEST
POST https://someAPI.com/us/oauth/v2/authorize?response_type=code&client_id=blahblahblah&redirect_uri=someOtherSite.com HTTP/1.1
Accept: application/json, application/xml, text/json, text/x-json, text/javascript, text/xml
User-Agent: RestSharp/105.2.3.0
Content-Type: application/x-www-form-urlencoded
Host: someAPI.com
Content-Length: 98
Accept-Encoding: gzip, deflate

username=someuser&password=somepassword&action=Log%20In&sessionID=someSessionId

Answer 1

变化：

https.request(options, function(res) {
    var str = "";
    res.on('data', function(data){
        str+=data;
    });
    res.on('end', function() {
        console.log(str);
    });
});

收件人：

var apiCall = https.request(options, (res) => {
    console.log('statusCode:', res.statusCode);
    console.log('headers:', res.headers);

    res.on('data', (d) => {
        process.stdout.write(d);
    });
});

apiCall.on("error", (e) => {console.error(e)});
apiCall.end();