Python SOAP 客户端，带有 suds 的 WSDL 调用给出传输错误 401 未经授权用于 HTTP 基本身份验证

Question

背景

我正在使用 Python 2.7.3 构建一个 SOAP 客户端，并使用 Canonical 提供的 suds 0.4.1 库。服务器正在通过 HTTPS 使用基本身份验证。

问题

无法通过服务器上的身份验证，甚至无法访问 WSDL。我收到以下错误：

suds.transport.TransportError：HTTP 错误 401：未经授权

尝试解析和编码

我已经尝试了suds documentation 中描述的两种身份验证方法，但在client = Client(url, ...) 行中仍然出现上述错误。我已经确认了在网络浏览器中连接的凭据和能力，这一切正常。

在声明wsdl_url、username和password之后，我尝试了：

client = Client(url=wsdl_url, username=username, password=password)

# as well as:

t = HttpAuthenticated(username=username, password=password)
client = Client(url=wsdl_url, transport=t)

# and even:

t = HttpAuthenticated(username=username, password=password)
t.handler = urllib2.HTTPBasicAuthHandler(t.pm)
t.urlopener = urllib2.build_opener(t.handler)
client = Client(url=wsdl_url, transport=t)

最后一个似乎，至少，从another question about HTTP authentication with suds 中的 WSDL URL 获得响应。

其他说明

这个问题与这个similar question 不同，因为我使用的是：

from suds.transport.https import HttpAuthenticated
# not:
# from suds.transport.http import HttpAuthenticated

从 Traceback 中，client = Client(url, ...) 调用显然命中了 suds.transport.https.py：

File "/usr/lib/python2.7/dist-packages/suds/client.py", line 112, in __init__ self.wsdl = reader.open(url)
File "/usr/lib/python2.7/dist-packages/suds/reader.py", line 152, in open d = self.fn(url, self.options)
File "/usr/lib/python2.7/dist-packages/suds/wsdl.py", line 136, in __init__ d = reader.open(url)
File "/usr/lib/python2.7/dist-packages/suds/reader.py", line 79, in open d = self.download(url)
File "/usr/lib/python2.7/dist-packages/suds/reader.py", line 95, in download fp = self.options.transport.open(Request(url))
File "/usr/lib/python2.7/dist-packages/suds/transport/https.py", line 60, in open return  HttpTransport.open(self, request)
File "/usr/lib/python2.7/dist-packages/suds/transport/http.py", line 64, in open raise TransportError(str(e), e.code, e.fp)

我错过了什么？

Answer 1

suds 没有将授权标头添加到请求中，因此我手动设置了它：

import base64

# code excluded for brevity

base64string = base64.encodestring('%s:%s' % (username, password)).replace('\n', '')
authenticationHeader = {
    "SOAPAction" : "ActionName",
    "Authorization" : "Basic %s" % base64string
}
client = Client(url=wsdl_url, headers=authenticationHeader)

Answer 2

你可以使用 SOAPpy

import SOAPpy, base64

class myHTTPTransport(SOAPpy.HTTPTransport):
    username = None
    passwd = None

    @classmethod
    def setAuthentication(cls,u,p):
        cls.username = u
        cls.passwd = p

    def call(self, addr, data, namespace, soapaction=None, encoding=None, http_proxy=None, config=SOAPpy.Config, timeout=None):

        if not isinstance(addr, SOAPpy.SOAPAddress):
          addr = SOAPpy.SOAPAddress(addr, config)

        if self.username != None:
          addr.user = self.username+":"+self.passwd

        return SOAPpy.HTTPTransport.call(self, addr, data, namespace, soapaction, encoding, http_proxy, config)


if __name__ == '__main__':

  # code for authenticating the SOAP API calls
  myHTTPTransport.setAuthentication('admin', 'admin')

  # Getting the instance of Server
  Baton = SOAPpy.WSDL.Proxy(<WSDL PATH>, transport=myHTTPTransport)

  # your code goes here
  ...