HTTP GET 的问题

Question

我在让 HTTP GET 工作时遇到了一些麻烦。我尝试过使用 OKHttp 库和默认的 android HTTP 客户端。问题是当我使用默认的 http 客户端时，我在响应正文中得到了这个

org.apache.http.conn.BasicManagedEntity@424ab550 

当我使用 okhttp 库时

com.squareup.okhttp.Call$RealResponseBody@424a6c58 

假设响应正文包含一个 JSON 对象。如果我将 URL 粘贴到浏览器窗口中，则 JOSN 会正确返回。我还检查了服务器日志，并且响应从服务器正确发送。我正在从异步类调用 HTTP GET 方法。

使用默认 Android HTTP 客户端的 GET 方法：

public String getData(String url)
{

    Log.w("Rakshak", "in the get Data data method");

    Log.w("Rakshak", "URL: "+url);

    HttpClient client = new DefaultHttpClient();
    HttpConnectionParams.setConnectionTimeout(client.getParams(), 20000000); //Timeout Limit
    HttpResponse httpResponse;
    try {
            Log.w("Rakshak", "in the get data try");
            HttpGet get = new HttpGet(url);
            httpResponse = client.execute(get);
            String response = httpResponse.getEntity().toString();
            Log.w("Rakshak", "Get responce: "+response); // this posts "org.apache.http.conn.BasicManagedEntity@424ab550" insted of the JSON that am supposed to get
            return response;

        } catch(Exception e) 
        {
                e.printStackTrace();

        }
    return "1";
}

使用 OkHTTP 库的 GET 方法：

public String getData(String url)
{
    OkHttpClient client = new OkHttpClient();

    //Log.w("Rakshak", "in the get Data data method ");

    //Log.w("Rakshak", "URL: "+url);

    Request request = new Request.Builder()
                                 .url(url)
                                 .build();

    try {
        Response response = client.newCall(request).execute();

        response.toString();


        Log.w("Rakshak", " in the service handeler"+response.body().toString()); // this posts "com.squareup.okhttp.Call$RealResponseBody@424a6c58" insted of the JSON that I supposed to get in the body.

        return response.body().toString();

    } catch (IOException e) {           
        e.printStackTrace();

        return "failed";
    }


}

我做错了什么，当我在浏览器窗口中通过相同的 url 时，为什么我无法从应用程序中获得正确的响应？

如果您需要查看更多代码，请告诉我。

干杯

Answer 1

试试这个代码：

class PlaceOrder extends AsyncTask<Void, Void, Void> {

        @Override
        protected Void doInBackground(Void... params) {

            // TODO Auto-generated method stub

            try {

                HttpClient httpClient = new DefaultHttpClient();

                HttpPost httpPst = new HttpPost(

                "yout_url");

                ArrayList<NameValuePair> parameters = new ArrayList<NameValuePair>(

                2);

                parameters.add(new BasicNameValuePair("username", "apple"));

                parameters.add(new BasicNameValuePair("pw", "apple"));

                parameters.add(new BasicNameValuePair("email",
                        "apple@gmail.com"));

                parameters.add(new BasicNameValuePair("name", "apple"));

                httpPst.setEntity(new UrlEncodedFormEntity(parameters));

                HttpResponse httpRes = httpClient.execute(httpPst);

                String str = convertStreamToString(
                        httpRes.getEntity().getContent()).toString();

                Log.i("mlog", "outfromurl" + str);

            } catch (UnsupportedEncodingException e) {

                // TODO Auto-generated catch block

                e.printStackTrace();

            } catch (ClientProtocolException e) {

                // TODO Auto-generated catch block

                e.printStackTrace();

            } catch (IOException e) {

                // TODO Auto-generated catch block

                e.printStackTrace();

            }

            return null;

        }

    }

    public static String convertStreamToString(InputStream is) {

        BufferedReader reader = new BufferedReader(new InputStreamReader(is));

        StringBuilder sb = new StringBuilder();

        String line = null;

        try {

            while ((line = reader.readLine()) != null) {

                sb.append(line + "\n");

            }

        } catch (Exception e) {

            e.printStackTrace();

        } finally {

            try {

                is.close();

            } catch (IOException e) {

                e.printStackTrace();

            }

        }

        return sb.toString();

    }