获取当前正在运行的 exe 名称（不是路径）[重复]

Question

嘿，所以我想获取当前正在运行的 exe 的名称 这是我尝试做的事情

#include <iostream>
#include <windows.h>

using namespace std;

int main()
  {
  char filename[ MAX_PATH ];
  DWORD size = GetModuleFileNameA( NULL, filename);
  if (size)
    cout << "EXE file name is: " << filename << "\n";
  else
    cout << "Could not fine EXE file name.\n";
  return 0;
  }

但它也获得了 exe 的路径，但我只需要 exe 名称有什么帮助吗？

Answer 1

第一个命令行参数是当前程序的名称

#include <iostream>
#include <string>
#include <windows.h>
#include <algorithm>

int main(int argc, char** argv)
{
    if (argc > 0)
        std::cout << argv[0] << std::endl;
    else {
        //some other method has to be used, use OP's suggestion
        char filename[ MAX_PATH ];
        DWORD size = GetModuleFileNameA( NULL, filename, MAX_PATH);
        if (!size) {
            std::cout << "Could not fine EXE file name.\n";
            return -1;
        }

        //Remove everything before the last "\"
        std::string name = filename;
        auto it = std::find(name.rbegin(), name.rend(), '\\'); //escape the escape character
        if (it != name.rend()) {
            name.erase(name.begin(), it.base());
        }

        std::cout << filename << std::endl;

    }
}