【发布时间】：2013-07-19 01:32:42
【问题描述】：
我正在使用 AJAX 联系表单，但它不发送邮件。我尝试了很多东西，但我真的不知道问题是什么。
<!-- START CONTACT FORM -->
<div id="contact_form" class="grid_6" style="margin:0;">
<div class="form-success">
<p>Ju falemnderit, mesazhi juaj eshte derguar!</p>
</div>
<div class="contact-form">
<form action="contact-form/send.php" method="post" class="form">
<label>Emri dhe mbiemri</label>
<input class="text" type="text" name="name">
<label>E-Mail</label>
<input class="text" type="text" name="email">
<!--
<label>Subject</label>
<input class="text" type="text" name="subject">
-->
<label>Koment</label>
<textarea name="message" rows="8" cols="60"></textarea>
<a href="javascript:;" id="submit" class="button">Dergo Email</a>
<div class="loading"></div>
</form>
</div>
</div>
<!-- END CONTACT FORM -->
这是contact-form/send.php
<?php
//Your e-mail address goes here:
$to = "lorentsh@hotmail.com";
//
//Retrieve form data.
//GET - user submitted data using AJAX
//POST - in case user does not support javascript, we'll use POST instead
$name = ($_GET['name']) ? $_GET['name'] : $_POST['name'];
$email = ($_GET['email']) ?$_GET['email'] : $_POST['email'];
$subject = ($_GET['subject']) ?$_GET['subject'] : $_POST['subject'];
$comment = ($_GET['comment']) ?$_GET['comment'] : $_POST['message'];
//flag to indicate which method it uses. If POST set it to 1
if ($_POST) $post=1;
//Include email validator
require 'email-validator.php';
$validator = new EmailAddressValidator();
//Simple server side validation for POST data, of course, you should validate the email
if (!$name) $errors[count($errors)] = 'Please enter your name.';
if (!$email) $errors[count($errors)] = 'Please enter your email.';
if (!$comment) $errors[count($errors)] = 'Please enter your comment.';
$email = strip_tags($email);
if (!$validator->check_email_address($email)) {
$errors[count($errors)] = 'Invalid email address.';
}
//if the errors array is empty, send the mail
if (!$errors) {
//sender
$from = $name . ' <' . $email . '>';
//Structure of the message:
$subject = 'Message from ' . $name;
$message = '
<!DOCTYPE html>
<head></head>
<body>
<table>
<tr><td>Name:</td><td>' . $name . '</td></tr>
<tr><td>Email:</td><td>' . $email . '</td></tr>
<tr><td>Subject:</td><td>' . $subject . '</td></tr>
<tr><td>Message:</td><td>' . nl2br($comment) . '</td></tr>
</table>
</body>
</html>';
//End of the message structure
//send the mail
$result = sendmail($to, $subject, $message, $from);
//if POST was used, display the message straight away
if ($_POST) {
if ($result) echo 'Thank you! We have received your message.';
else echo 'Sorry, unexpected error. Please try again later';
//else if GET was used, return the boolean value so that
//ajax script can react accordingly
//1 means success, 0 means failed
} else {
echo $result;
}
//if the errors array has values
} else {
//display the errors message
for ($i=0; $i<count($errors); $i++) echo $errors[$i] . '<br/>';
echo '<a href="../contact.html">Back</a>';
exit;
}
//Simple mail function with HTML header
function sendmail($to, $subject, $message, $from) {
$headers = "MIME-Version: 1.0" . "\r\n";
$headers .= "Content-type:text/html;charset=iso-8859-1" . "\r\n";
$headers .= 'From: ' . $from . "\r\n";
$result = mail($to,$subject,$message,$headers);
if ($result) return 1;
else return 0;
}
?>
你能告诉我问题出在哪里吗？到 index.html 或 send.php。我需要你们的帮助。
【问题讨论】：
-
他们告诉我这是 ajax 联系表，但这是我的全部，需要帮助
-
您确定您的服务器配置正确以发送邮件吗？你可能想在你的 sendmail 函数中添加一些调试语句并检查控制是否在那里。
-
更改 $from = $name 时会发生什么。 ' ';到 $from = $name; ?
-
其实我对服务器一窍不通，能指导我找服务器吗？
-
嗨洛伦特，我不明白为什么我在回答你的问题时得到一个无用的标记。我在我的服务器上使用我的建议尝试了您的代码，我还删除了您的 php 文件中的验证器，因为它不存在并且您没有向它提供您的问题，并且它有效。请在我编辑的答案中找到下面的结果截图。谢谢。
标签： php html forms contact contact-form