【发布时间】:2014-11-16 23:27:20
【问题描述】:
我正在尝试设置一个 node.js 应用程序,该应用程序可以接收连接并在套接字结束后仍监听端口 9001。我怎样才能做到这一点?这是我当前的代码(在 socket.end() 之后它不会关闭,但它不会接受任何其他连接):
var net = require('net');
var mySocket;
var server = net.createServer(function(socket) {
mySocket = socket;
mySocket.on("connect", onConnect);
mySocket.on("data", onData);
});
function onConnect() {
console.log("Connected");
}
function onData(command) {
if (command == "exit") {
console.log("Exiting");
mySocket.end();
}
}
console.log("Waiting for incoming connections");
server.listen(9001);
我试图在socket.end(); 之后添加另一个server.listen(9001);,但我收到一条:Error: listen EADDRINUSE 消息。
此外,该代码是否能够同时接收来自不同地址的多个连接,并分别处理它们?
这是完整的代码。执行时,node.js 接收到来自 Flash 应用程序的 4 个命令,并且正常工作(除了 onConnect() 函数似乎从未被调用),并且“exit;”命令正确关闭套接字,但如果我重新加载 Flash 应用程序,它不会连接到服务器
var net = require('net');
const PACKET_SEPARATOR = 59 // ;
var connection_ack = false;
var counter = 0;
var server = net.createServer(function(socket) {
function onConnect() {
console.log("Connected to Flash");
}
function dataHandler(command) {
if (command[command.length - 1] != String.fromCharCode(PACKET_SEPARATOR) && connection_ack) {
console.log("SEP : " + PACKET_SEPARATOR + " - last : " + command[command.length - 1] + " - ack " + connection_ack);
console.log("CAUGHT EXCEPTION : WRONG PACKET FORMAT --- " + command + " --- " + command.length);
}
if (command == "exit;") {
console.log("Received exit request from " + socket.address().address + ":" + socket.address().port + " (" + socket.address().family + "). Ending connection...");
socket.end();
}
else if (command == "<policy-file-request/>\0") {
socket.write('<cross-domain-policy>\n<allow-access-from domain="*" to-ports="*" />\n</cross-domain-policy>\0', 'utf8');
console.log("Policy file sent to " + socket.address().address + ":" + socket.address().port);
player1.pxacceleration = 0;
player1.pyacceleration = 0;
connection_ack = true;
}
else {
console.log("Got data from " + socket.address().address + ":" + socket.address().port + " (" + socket.address().family + ")");
console.log("--> " + command);
counter++;
socket.write("Received " + counter + " commands;", 'utf8');
console.log("Sending : Received " + counter + " commands;");
}
}
function onData(d) {
var command = "";
for (i=0; i <= d.length - 1; i++) {
command += String.fromCharCode(d[i]);
if (d[i] == PACKET_SEPARATOR || i == d.length - 1 && !connection_ack) {
dataHandler(command);
command = "";
}
}
}
socket.on("connect", onConnect);
socket.on("data", onData);
});
console.log("Ready. Waiting for incoming connections");
server.listen(9001);
server.listen(80); //TODO : Remove?
【问题讨论】:
-
除非你关闭
server,否则你想要的应该已经发生了。 -
server应该已经比个人sockets 寿命更长。对于多个客户端,server将创建多个可以同时打开和活动的sockets。另一方面,全局mySocket无法帮助server正确支持多个客户端,因为它只能存储其中一个。 -
将
mySocket用作全局非常糟糕。一旦您同时连接了多个套接字,您的mySocket变量就会被覆盖。使 onData 成为一个局部函数,您可以直接引用socket而无需使用全局。 -
我不确定你的意思。能给我举个小例子吗?