【发布时间】:2014-12-16 07:11:16
【问题描述】:
我有以下两个查询:
查询 #1:
(SELECT
pl.c_project_Id, pl.c_projectphase_Id, pl.c_projecttask_Id, pl.m_product_Id,
pj.name as projectname, ph.name as phasename, pt.name as taskname, pd.name as prodname,
round(pl.plannedqty, 2) as planqty, round(pl.plannedprice, 2) as planrate,
round(pl.plannedamt, 2) as planamt
FROM adempiere.c_projectline pl
LEFT JOIN adempiere.c_project pj ON pl.c_project_id = pj.c_project_id
LEFT JOIN adempiere.c_projectphase ph ON pl.c_projectphase_id = ph.c_projectphase_id
LEFT JOIN adempiere.c_projecttask pt ON pl.c_projecttask_id = pt.c_projecttask_id
LEFT JOIN adempiere.m_product pd ON pl.m_product_id = pd.m_product_id
WHERE pl.c_project_id = 1000001 AND pl.ad_client_id = 1000000
ORDER BY ph.c_projectphase_id, pt.c_projecttask_id)
输出为:11 列 16 行
查询 #2:
(SELECT
fa.c_project_id, fa.c_projectphase_id, fa.c_projecttask_id, fa.m_product_id,
pj.name as costprojectname, ph.name as costphasename, pt.name as costtaskname,
pd.name as costprodname,
abs(fa.qty) as costqty, round((fa.amtacctdr/fa.qty), 2) as costrate,
round(sum(fa.amtacctdr), 0) as costamt
FROM adempiere.fact_acct fa
LEFT JOIN adempiere.c_project pj ON fa.c_project_id = pj.c_project_id
LEFT JOIN adempiere.c_projectphase ph ON fa.c_projectphase_id = ph.c_projectphase_id
LEFT JOIN adempiere.c_projecttask pt ON fa.c_projecttask_id = pt.c_projecttask_id
LEFT JOIN adempiere.m_product pd ON fa.m_product_id = pd.m_product_id
WHERE fa.c_project_id = 1000001 AND (fa.gl_category_id = 1000006 OR fa.gl_category_id = 1000005)
AND fa.qty > 0 AND fa.c_project_id is not null
GROUP BY fa.m_product_id, fa.c_project_id, fa.c_projectphase_id, fa.c_projecttask_id,
fa.qty, fa.amtacctdr,
pj.name, ph.name, pt.name, pd.name)
输出为:11 列 6 行
我想水平加入这些查询,显示所有列但行不应该重复。当我应用联合加入它们时,结果显示重复的行。我该如何处理这个问题?
【问题讨论】:
-
如何匹配查询之间的行?
标签: sql postgresql-9.1