统一数组结构

Question

我需要你的帮助， 我有一个数组，其中包含每个月（12 个月）执行的任务数，如下所示：

[      
  ["Ilhem", "Ben Salah", 4, 1],     
  ["Ilhem", "Ben Salah", 3, 2],
  ["Ilhem", "Ben Salah", 3, 3],
  ["Ilhem", "Ben Salah", 3, 4],
  ["Sghaier", "Mahmoud", 1, 1]
]

现在我需要一个这样的数组：

[
["Ilhem", "Ben Salah", 4, 1],
["Ilhem", "Ben Salah", 0, 2],
["Ilhem", "Ben Salah", 0, 3],
["Ilhem", "Ben Salah", 0, 4],
["Ilhem", "Ben Salah", 0, 5],
["Ilhem", "Ben Salah", 0, 6],
["Ilhem", "Ben Salah", 0, 7],
["Ilhem", "Ben Salah", 0, 8],
["Ilhem", "Ben Salah", 0, 9],
["Ilhem", "Ben Salah", 0, 10],
["Ilhem", "Ben Salah", 0, 11],
["Ilhem", "Ben Salah", 0, 12],
["Sghaier", "Mahmoud", 7, 1],
["Sghaier", "Mahmoud", 0, 2],
["Sghaier", "Mahmoud", 0, 3],
["Sghaier", "Mahmoud", 0, 4],
["Sghaier", "Mahmoud", 0, 5],
["Sghaier", "Mahmoud", 0, 6],
["Sghaier", "Mahmoud", 0, 7],
["Sghaier", "Mahmoud", 0, 8],
["Sghaier", "Mahmoud", 0, 9],
["Sghaier", "Mahmoud", 0, 10],
["Sghaier", "Mahmoud", 0, 11],
["Sghaier", "Mahmoud", 0, 12]

]

如何继续，我很困惑。

Answer 1

首先创建一个使用名称作为键的对象和一个子对象，以使用月份编号作为键来存储该名称的现有月份的数组

然后使用 1-12 的循环，查看该名称是否存在月份，如果不存在则填写缺失的项目

function fillMonthHoles(data) {
  var groupByName = {}
  data.forEach(function(arr) {
    var baseArr = arr.slice(0, 2), nameKey = baseArr.join('|');
    this[nameKey] = this[nameKey] || {baseArr : baseArr};   
    this[nameKey][arr[3]] = arr;
  }, groupByName);

  return Object.keys(groupByName).reduce(function(a, key) {
    var baseArr = groupByName[key].baseArr
    for (var i = 1; i < 13; i++) {
      var arr = groupByName[key][i];
      if (!arr) {
        arr = baseArr.slice().concat([0, i]);
      }
      a.push(arr)
    }
    return a
  }, []);

}

var res = fillMonthHoles(data);
// loop over results and log each subarray for demo only
res.forEach(a => console.log(JSON.stringify(a)))

.as-console-wrapper {
  max-height: 100%!important;
}

<script>
  var data = [
    ["Ilhem", "Ben Salah", 4, 1],
    ["Ilhem", "Ben Salah", 3, 2],
    ["Ilhem", "Ben Salah", 3, 3],
    ["Ilhem", "Ben Salah", 3, 4],
    ["Sghaier", "Mahmoud", 1, 1]
  ]
</script>

Answer 2

这很好用。

var  a = [      
  ["Ilhem", "Ben Salah", 4, 1],     
  ["Ilhem", "Ben Salah", 3, 2],
  ["Ilhem", "Ben Salah", 3, 3],
  ["Ilhem", "Ben Salah", 3, 4],
  ["Sghaier", "Mahmoud", 1, 1],
  ["Sghaier", "Mohammad", 15, 2],
];

var result = [];
while(a.length>0)
{
    var item = a[0], firstname = item[0], lastname = item[1];
    var matchedarr = a.filter(function(item){
            return (item[0] == firstname && item[1] == lastname);
        });
    for(var j=1;j<=12;j++)
    {
        var arr = matchedarr.filter(function(item){
            return item[3]==j;
        });
        arr = arr[0] || [item[0],item[1],0,j];
        result.push(arr);
    }
    a = a.filter(function(item){
        return item[0]!==firstname || item[1]!==lastname;
    });
}

console.log(result);