【发布时间】：2015-09-02 09:29:26
【问题描述】：
我正在（春季开发中的新手）为我的应用程序创建 REST API，CRUD 操作已成功实施，但现在我想实施服务器端验证。我还读到有几种方法可以实现验证。
- 使用给定的注释 -> @notempty、@email 等...
- 使用自定义验证 -> 扩展验证器
我想在我的应用程序中实现它们，参考那个，
这是一种好方法吗？
或
还有其他方式可以实现验证吗？
控制器
@RestController
public class EmployeeController {
@Autowired
DataServices dataServices;
@Autowired
EmployeeValidator employeeValidator;
@InitBinder
protected void initBinder(WebDataBinder binder) {
binder.addValidators(employeeValidator);
}
@RequestMapping(value = "/employee/", method = RequestMethod.POST)
public ResponseEntity<Object> createUser(
@Valid @RequestBody Employee employee,
UriComponentsBuilder ucBuilder) throws Exception,
DataIntegrityViolationException {
if (dataServices.addEmployee(employee) == 0) {
Error error = new Error(1, "Data integrity violation",
"Email id is already exists.");
return new ResponseEntity<Object>(error, HttpStatus.CONFLICT);
}
HttpHeaders headers = new HttpHeaders();
headers.setLocation(ucBuilder.path("/employee/{id}")
.buildAndExpand(employee.getId()).toUri());
Status status = new Status(1, "Employee has been added successfully.");
return new ResponseEntity<Object>(status, headers, HttpStatus.CREATED);
}
}
错误处理程序
@ControllerAdvice
public class RestErrorHandler {
private static final Logger logger = Logger
.getLogger(RestErrorHandler.class);
private MessageSource messageSource;
@Autowired
public RestErrorHandler(MessageSource messageSource) {
this.messageSource = messageSource;
}
@ExceptionHandler(MethodArgumentNotValidException.class)
@ResponseStatus(HttpStatus.BAD_REQUEST)
@ResponseBody
public ValidationErrorDTO processValidationError(
MethodArgumentNotValidException ex) {
logger.debug("Handling form validation error");
BindingResult result = ex.getBindingResult();
List<FieldError> fieldErrors = result.getFieldErrors();
return processFieldErrors(fieldErrors);
}
private ValidationErrorDTO processFieldErrors(List<FieldError> fieldErrors) {
ValidationErrorDTO dto = new ValidationErrorDTO();
for (FieldError fieldError : fieldErrors) {
String localizedErrorMessage = resolveLocalizedErrorMessage(fieldError);
dto.addFieldError(fieldError.getField(), localizedErrorMessage,
fieldError.getDefaultMessage());
}
return dto;
}
private String resolveLocalizedErrorMessage(FieldError fieldError) {
Locale currentLocale = LocaleContextHolder.getLocale();
String localizedErrorMessage = messageSource.getMessage(fieldError,
currentLocale);
// If a message was not found, return the most accurate field error code
// instead.
// You can remove this check if you prefer to get the default error
// message.
if (localizedErrorMessage.equals(fieldError.getDefaultMessage())) {
String[] fieldErrorCodes = fieldError.getCodes();
localizedErrorMessage = fieldErrorCodes[0];
}
return localizedErrorMessage;
}
}
验证器
@Component
public class EmployeeValidator implements Validator {
public boolean supports(Class clazz) {
return Employee.class.isAssignableFrom(clazz);
}
public void validate(Object target, Errors errors) {
ValidationUtils.rejectIfEmptyOrWhitespace(errors, "firstName", errors
.getFieldError().getCode(), "First name is required.");
ValidationUtils.rejectIfEmptyOrWhitespace(errors, "lastName", errors
.getFieldError().getCode(),
"Last name is required.");
ValidationUtils.rejectIfEmptyOrWhitespace(errors, "email", errors
.getFieldError().getCode(),
"Email is required.");
}
}
型号
@Entity
@Table(name = "employee")
@JsonIgnoreProperties({ "hibernateLazyInitializer", "handler" })
public class Employee implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@GeneratedValue
@Column(name = "id")
private long id;
// @NotEmpty(message = "Please enter first name")
@Column(name = "first_name")
private String firstName;
// @NotEmpty(message = "Please enter last name")
@Column(name = "last_name")
private String lastName;
// @NotEmpty(message = "Please enter email address")
@Email(message = "Please enter valid email address")
@Column(name = "email", unique = true)
private String email;
@NotEmpty(message = "Please enter mobile number")
@Size(min = 10, message = "Please enter valid mobile number")
@Column(name = "phone")
private String phone;
//Getter and Setter
}
【问题讨论】：
-
注解：如果您开始使用 JSON 向 UI 公开您的实体（员工），您应该使用 Spring Data Rest，它正是为这种需求而设计的。关于验证，我正在使用这种策略。
-
绑定结果有很多可用的验证示例。你到底想达到什么目标？
标签： java spring validation