【发布时间】：2014-01-13 14:37:24
【问题描述】：
我想通过 php 显示 mysql 数据库中的用户详细信息，并在 android textview 中显示。场景是这样的：当用户登录到他的帐户时，他将被重定向到包含 4 个按钮的仪表板，即：新闻源、个人资料、日历和关于。当用户单击配置文件按钮时，用户详细信息（例如他的姓氏、名字、中间首字母等）将显示在文本视图中。当我运行我的应用程序时，它不显示任何内容，但在我的 php 脚本中它返回用户详细信息。这里似乎有什么问题？
这是我的java代码：
package sscr.stag;
import java.util.ArrayList;
import java.util.List;
import org.apache.http.NameValuePair;
import org.apache.http.message.BasicNameValuePair;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import android.app.Activity;
import android.app.ProgressDialog;
import android.content.SharedPreferences;
import android.os.AsyncTask;
import android.os.Bundle;
import android.preference.PreferenceManager;
import android.util.Log;
import android.widget.TextView;
public class AdProfile extends Activity {
// All xml labels
TextView txtFname;
TextView txtMname;
TextView txtLname;
// Progress Dialog
private ProgressDialog pDialog;
// Creating JSON Parser object
JSONParser jsonParser = new JSONParser();
// Profile json object
JSONArray user;
JSONObject hay;
// Profile JSON url
private static final String PROFILE_URL ="http://www.stagconnect.com/StagConnect/admin/TestProfile.php";
// ALL JSON node names
private static final String TAG_PROFILE = "user";
// private static final String TAG_ID = "id";
private static final String TAG_USERNAME = "username";
private static final String TAG_FIRSTNAME = "first_name";
private static final String TAG_MIDDLENAME = "middle_initial";
private static final String TAG_LASTNAME = "last_name";
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.adminprofile);
txtFname = (TextView) findViewById(R.id.fname);
txtMname = (TextView) findViewById(R.id.mname);
txtLname = (TextView) findViewById(R.id.lname);
// Loading Profile in Background Thread
new LoadProfile().execute();
}
class LoadProfile extends AsyncTask<String, String, String> {
public void test(){
hay = new JSONObject();
// Storing each json item in variable
try {
String firstname = hay.getString(TAG_FIRSTNAME);
String middlename = hay.getString(TAG_MIDDLENAME);
String lastname = hay.getString(TAG_LASTNAME);
// displaying all data in textview
txtFname.setText("Firstname: " + firstname);
txtMname.setText("Middle Name: " + middlename);
txtLname.setText("Last Name " + lastname);
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
@Override
protected void onPreExecute() {
super.onPreExecute();
pDialog = new ProgressDialog(AdProfile.this);
pDialog.setMessage("Loading profile ...");
pDialog.setIndeterminate(false);
pDialog.setCancelable(false);
pDialog.show();
}
/**
* getting Profile JSON
* */
protected String doInBackground(String... args) {
// Building Parameters
SharedPreferences sp = PreferenceManager.getDefaultSharedPreferences(AdProfile.this);
String post_username = sp.getString("username", "anon");
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("username", post_username));
// getting JSON string from URL
JSONObject json = jsonParser.makeHttpRequest(PROFILE_URL, "POST",
params);
// Check your log cat for JSON reponse
Log.d("Profile JSON: ", json.toString());
try {
// profile json object
user = json.getJSONArray(TAG_PROFILE);
} catch (JSONException e) {
e.printStackTrace();
}
return null;
}
protected void onPostExecute(String file_url) {
// dismiss the dialog after getting all products
pDialog.dismiss();
// updating UI from Background Thread
test();
}
}
}
这是我的 php 脚本：
<?php
require('admin.config.inc.php');
if (!empty($_POST)) {
//initial query
$query = "Select last_name, first_name, middle_initial, designation FROM admin where username = :user";
$query_params = array(':user' => $_POST['username']);
//execute query
try {
$stmt = $db -> prepare($query);
$result = $stmt -> execute($query_params);
} catch (PDOException $ex) {
$response["success"] = 0;
$response["message"] = "Database Error!";
die(json_encode($response));
}
// Finally, we can retrieve all of the found rows into an array using fetchAll
$rows = $stmt -> fetchAll();
if ($rows) {
$response["success"] = 1;
$response["message"] = "Post Available!";
$response["user"] = array();
foreach($rows as $row) {
$user = array();
$user["designation"] = $row["designation"];
$user["middlename"] = $row["middle_initial"];
$user["firstname"] = $row["first_name"];
$user["lastname"] = $row["last_name"];
//update our repsonse JSON data
array_push($response["user"], $user);
}
// echoing JSON response
echo json_encode($response);
} else {
$response["success"] = 0;
$response["message"] = "No user available!";
die(json_encode($response));
}
} else {}
?>
<form action="TestProfile.php" method="POST">
Username: <input type="text" name="username">
<input type="submit" value="Submit">
</form>
这里是我的 php 脚本的输出（JSON 响应）：
{"success":1,"message":"Post Available!","user":[{"designation":"Student Affairs Office in charge","middlename":"","firstname":"test","lastname":"test"}]}
【问题讨论】：
-
hay = new JSONObject();应该是hay = new JSONObject("jsonstrin"); -
我收到此错误：未处理的异常类型 JSONException
-
json和user对象被完全忽略。你应该在哪里展示一些东西？ -
我想在 textview 中显示，先生，对不起，我不知道该怎么做，我只是 android 的新手
-
@IamAndroida 请看我的回答你的问题一定会解决的