来自 MySQL 的 Json 和 PHP

Question

嗨，我正在用 php 抓取我的桌子并得到这个输出

{"id":"1","player":"123","name":"his_name","reason":"reason text","instance":"1","lastupdated":"datetime"}

但是我希望得到这样的东西

text{"id":"1","player":"123","name":"his_name","reason":"reason text","instance":"1","lastupdated":"datetime"}

当前 php：

mysql_connect($dbhost.':'.$dbport, $dbuser, $dbpass) or die (mysql_error());
mysql_select_db("dbname") or die (mysql_error());

$sth = mysql_query("SELECT *"."FROM `table_name` Order By id Desc;");
$rows = array();
while($r = mysql_fetch_assoc($sth)) {
    $rows[] = $r;
}

print json_encode($rows);

数据库结构：

player | name | reason | instance | lastupdated

任何帮助将不胜感激

Answer 1

如果你想在前面加上文字，你可以使用字符串连接操作符来打印：

print "text" . json_encode($rows);

这对你有用吗？但是text 的内容应该是什么？

Answer 2

如果您只想在从数据库获得的完整结果集之前添加一个键。正如我从您的示例链接中了解到的那样。

然后你可以像这样更新你的代码：

 // Assuming $rows is already populated with desired data.

$res = array();
$res['text'] = $rows;

print_r(json_encode($res));

输出：

{"text":{"id":1,"player":123,"name":"his_name","reason":"reason text","instance":1,"lastupdated":"datetime"}}

希望对你有帮助。