以行格式而不是列返回查询

Question

目前我有 2 个表，一个列表表和一个日志表。通过以下查询，我试图获取特定日期的产品列表，并返回正确的输出。

with X as (
  select 
    l.*,
    (select status_from from logs where logs.refno = l.refno and logs.logtime >= '2021-10-01' order by logs.logtime limit 1) logstat
  from listings l
  where l.added_date < '2021-10-01'
)
, Y as (select X.*, ifnull(X.logstat, X.status) stat from X)
SELECT 
  status.text,
  COUNT(Y.id) AS c 
from status
left join Y on Y.stat = status.code
group by status.code, status.text;

这给出了这样的输出：

在这里，我已按 1 个日期过滤查询，在本例中为 2021-10-01。输出应如下所示：

Publish	Action	Let	Sold	Draft
0	3	0	1	1
0	2	0	1	2

Dbfiddle：https://dbfiddle.uk/?rdbms=mysql_8.0&fiddle=5e0b8d484a41ac9104d0fb002e7f9a3c

Answer 1

你可以试试下面的查询-

with X as (
  select 
    l.*,
    (select status_from from logs where logs.refno = l.refno and logs.logtime >= '2021-10-02' order by logs.logtime limit 1) logstat
  from listings l
  where l.added_date between '2021-10-01 00:00:00' and '2021-10-02 00:00:00'      -- Start and end date range.
)
, Y as (select X.*, ifnull(X.logstat, X.status) stat20211001 from X)
SELECT 
  added_date,
  COUNT(CASE WHEN status.text = 'Publish' THEN Y.id END) AS Publish,
  COUNT(CASE WHEN status.text = 'Action' THEN Y.id END) AS Action,
  COUNT(CASE WHEN status.text = 'Let' THEN Y.id END) AS Let,
  COUNT(CASE WHEN status.text = 'Sold' THEN Y.id END) AS Sold,
  COUNT(CASE WHEN status.text = 'Draft' THEN Y.id END) AS Draft
from status
join Y on Y.stat20211001 = status.code
group by added_date;

Demo.