关于mariaDB的插入动态列答案

【问题标题】：On the insertion dynamic column of mariaDB关于mariaDB的插入动态列
【发布时间】：2016-11-19 14:49:28
【问题描述】：

set @v1 = "'city', 'ITY', 'age', '20'";
select @v1;
insert into test values (11, 'hidy', column_create(@v1));

MariaDB 不支持插入形式的这个变量，并且

client Error at))
MariaDB :10.1.19
client :heidi 9.4.0.5130 
OS: Windows 10

如何以可变形式插入？因为我想在我的JAVA中使用JDBC来传递参数

【问题讨论】：

需要改进格式

标签： java mariadb mariadb-connect-engine

【解决方案1】：

您可以为 INSERT 使用准备好的语句。

MariaDB [test]> set @v1 = "'city', 'ITY', 'age', '20'";
Query OK, 0 rows affected (0.01 sec)

MariaDB [test]> set @q = concat("insert into test values(11, 'hidy', column_create(",@v1,"))");
Query OK, 0 rows affected (0.00 sec)

MariaDB [test]> select @q;
+--------------------------------------------------------------------------------+
| @q                                                                             |
+--------------------------------------------------------------------------------+
| insert into test values(11, 'hidy', column_create('city', 'ITY', 'age', '20')) |
+--------------------------------------------------------------------------------+
1 row in set (0.00 sec)

MariaDB [test]> prepare stmt from @q;
Query OK, 0 rows affected (0.00 sec)
Statement prepared

MariaDB [test]> execute stmt;
Query OK, 1 row affected (0.26 sec)

MariaDB [test]> select column_get(b,'city' as char(8)) from test;
+---------------------------------+
| column_get(b,'city' as char(8)) |
+---------------------------------+
| ITY                             |
+---------------------------------+
1 row in set (0.00 sec)

【讨论】：

谢谢。这个获取JSON值比MYSQL难