为什么这个 COUNT in HAVING 没有按预期工作？

Question

我正在使用以下查询来选择所有出现超过 3 次且带有状态 ID 的客户。该查询还计算客户状态 ID 出现的次数：

SELECT `bp_customer_id`, `status_id`, COUNT(`status_id`) FROM `bp_orders` 
GROUP BY `status_id`, `bp_customer_id` 
ORDER BY `bp_customer_id`  

它给出以下输出：

在上表中，客户 1000 出现了 3 次。所以我只想选择那些在表格中出现 3 次或 3 次以上的客户。我们如何做到这一点？我在上面的查询中使用了COUNT() 和HAVING，但没有运气。

SELECT `bp_customer_id`, `status_id`, COUNT(`status_id`) FROM `bp_orders` 
GROUP BY `status_id`, `bp_customer_id` 
HAVING COUNT(`bp_customer_id`) >= 3 
ORDER BY `bp_customer_id`

我哪里做错了？

Answer 1

尚未检查这是否可行，但进行子选择可能会有所帮助

SELECT A.`bp_customer_id`, A.`status_id`, COUNT(`status_id`) FROM `bp_orders` A, {
    SELECT COUNT(*) AS customerCount, `bp_customer_id` FROM `bp_orders` GROUP BY `bp_customer_id`
} B WHERE A.`bp_customer_id` = B.`bp_customer_id`
AND B.customerCount >= 3
GROUP BY A.`status_id`, A.`bp_customer_id` 
ORDER BY A.`bp_customer_id`  

Answer 2

如果您在输出结果中只需要bp_customer_id，请忽略SELECT 语句中的其他列

SELECT `bp_customer_id`
FROM `bp_orders` 
GROUP BY `bp_customer_id` 
HAVING COUNT(DISTINCT `bp_customer_id`) >= 3 
ORDER BY `bp_customer_id`

根据您的评论，您需要 bp_customer_id 以及 status_id 和 COUNT。因此，使用上述查询作为子查询并基于bp_customer_id，您也可以获得其他详细信息。所以工作查询是：

​SELECT `bp_customer_id`, 
       `status_id`, 
       COUNT(`status_id`) 
FROM `bp_orders` 
WHERE `bp_customer_id` IN (
    SELECT `bp_customer_id`
    FROM `bp_orders` 
    GROUP BY `bp_customer_id` 
    HAVING COUNT(DISTINCT `bp_customer_id`) >= 3 
) 
GROUP BY `bp_customer_id`, `status_id` 
ORDER BY `bp_customer_id`