作为 SELECT 的一部分，将 php 变量作为字符串传递给 mysql答案

【问题标题】：Passing a php variable as string to mysql as part of SELECT作为 SELECT 的一部分，将 php 变量作为字符串传递给 mysql
【发布时间】：2017-02-09 13:20:37
【问题描述】：

在设置具有动态日期的数据透视表时。在将我的第一个 mysql 查询生成的字符串插入到第二个时，我遇到了逻辑墙。

当我

echo $rowstring

回声生成

SUM( IF( `InvDate`='20160106', round(InvTotalIncl,2), 0 ) ) AS `20160106`,
SUM( IF( `InvDate`='20160107', round(InvTotalIncl,2), 0 ) ) AS `20160107`

通过以下查询测试输出：

    select InvOperCode,
    SUM( IF( `InvDate`='20160106', round(InvTotalIncl,2), 0 )     )
    AS `20160106`,
    SUM( IF( `InvDate`='20160107', round(InvTotalIncl,2), 0 ) ) 
    AS `20160107`
    FROM `invoice_hdr_tbl`
    where InvDate between '20160101' and '20160131'
    group by InvOperCode

我得到了我想要的结果。

但是，当我尝试将第一个查询作为字符串传递给第二个查询时

$result = mysql_query("select InvOperCode,'.$rowstring.'
FROM `invoice_hdr_tbl`
where InvDate between '20160101' and '20160131'
group by InvOperCode");

我收到错误“查询以显示表中的字段失败”这是我的代码行，所以我知道我的第二个数据库查询有错误。

if (!$result) {
    die("Query to show fields from table failed");

我认为我的字符串转换不正确，或者我的查询的“选择”部分中的变量引用不正确。

任何帮助将不胜感激。

PS 我离开了

echo $rowstring;

在我的代码中识别我正在查看查询并将回显声明为正确的点。无论出于何种原因，它都无法正确传递给我的数据库查询

到目前为止，这是我的代码。

$resultlength = mysql_query("SET SESSION group_concat_max_len = 1000000");


$concatresult = mysql_query("
select group_concat(distinct CONCAT('SUM( IF( `InvDate`=\'',`InvDate`,'\', round(InvTotalIncl,2), 0 ) ) AS `',`InvDate`,'`'))
as Data
FROM `invoice_hdr_tbl`
where InvDate between '20160101' and '20160131'
order by InvDate");
if (!$concatresult) {
    die("Query to show fields from table failed");
}

$rowarray = mysql_fetch_assoc($concatresult);

$rowstring = $rowarray['Data'];
echo $rowstring;


$result = mysql_query("select InvOperCode,'.$rowstring.'
FROM `invoice_hdr_tbl`
where InvDate between '20160101' and '20160131'
group by InvOperCode");

if (!$result) {
    die("Query to show fields from table failed");
}
$fields_num = mysql_num_fields($result);

echo "<h1>Sales Report </h1>";
echo "<table border='1'><tr>";
// printing table headers
for($i=0; $i<$fields_num; $i++)
{
    $field = mysql_fetch_field($result);
    echo "<td>{$field->name}</td>";
}
echo "</tr>\n";
while($row = mysql_fetch_row($result))
{
    echo "<tr>";


    foreach($row as $cell)
        echo "<td>$cell</td>";

    echo "</tr>\n";
}
mysql_free_result($result);

【问题讨论】：

标签： mysql variables select

【解决方案1】：

我找到了解决方案，它很简单却被忽视了：

$result = mysql_query("select InvOperCode,'.$rowstring.'
FROM `invoice_hdr_tbl`
where InvDate between '20160101' and '20160131'
group by InvOperCode");

应该是

 $result = mysql_query("select InvOperCode,$rowstring
    FROM `invoice_hdr_tbl`
    where InvDate between '20160101' and '20160131'
    group by InvOperCode");

【讨论】：