如何使用 hasOne 关系保存 Sequelize 中的条目？

Question

我有一个模型 Transaction 与 hasMany 关联到 StripePayment。

我想用相关的StripePayment 创建一个新的Transaction，如下所示：

await models.Transaction.create({
  amount,
  stripePayment: {
    stripeId: paymentIntent.id,
    status: stripePaymentStatuses[status],
    clientSecret: paymentIntent.client_secret,
  }
});

这会创建一个新的交易，但不会创建 stripePayment。

我的模型是这样的：

// transaction model
class Transaction extends Model {
    
  static associate(models) {
    this.hasOne(models.StripePayment, { 
      as: 'StripePayment',
      foreignKey: 'id'
    });
  }
}

Transaction.init(
  {
    id:{ 
      allowNull: false,
      primaryKey: true,
      type: DataTypes.UUID,
      defaultValue: DataTypes.UUIDV4
    },
    stripePaymentId: {
      type: DataTypes.UUID,
      allowNull: true,
      foreignKey: true,
      references: {
        model: stripePayment,
        key: 'id',
      },
    },
    amount: {
      type: DataTypes.INTEGER,
      allowNull: false,
    }
  },
  {
    sequelize,
    modelName: 'Transaction',
  }
);

// stripePayment
class StripePayment extends Model {
    
  static associate(models) {
    this.belongsTo(models.Transaction, { 
      as: 'Transaction', 
      foreignKey: 'stripePaymentId' 
    });
  }
}

StripePayment.init(
  {
    id:{ 
      allowNull: false,
      primaryKey: true,
      type: DataTypes.UUID,
      defaultValue: DataTypes.UUIDV4
    },
    // ...
  },
  {
    sequelize,
    modelName: 'StripePayment',
  }
);

当我将它传递给create 方法时，我觉得模型不知道stripePayment。我的结构正确吗？

如何使用相关的StripePayment 创建Transaction？

Answer 1

您只需要在调用create 方法时指明include 选项，参见creating with associations：

await models.Transaction.create({
  amount,
  // pay attention: this prop should be named exactly as an alias of a model and because it's `hasMany` you should wrap it into an array
  StripePayment: [{
    stripeId: paymentIntent.id,
    status: stripePaymentStatuses[status],
    clientSecret: paymentIntent.client_secret,
  }],
  include: [{
    model: StripePayment,  
    as: 'StripePayment',
  }]
});