【发布时间】：2015-05-07 15:23:44
【问题描述】：
如果同一表中已经存在一行，其中包含nick，我正在尝试在 MySQL 中插入一行。这是我正在尝试的查询：
INSERT IGNORE INTO gold_log (nick, amount, stream_online, modification_type, dt)
SELECT DISTINCT nick, 0, 0, 253, DATE_FORMAT(NOW(), '%Y-01-01 00:00:00')
FROM gold_log WHERE nick='PrestonConnors';
我得到结果：
Query OK, 2243 rows affected, 2 warnings (0.24 sec)
Records: 2243 Duplicates: 0 Warnings: 2
当我独立运行 SELECT 语句时，它只返回一个结果（这是我所期望的）：
mysql> SELECT DISTINCT nick, 0, 0, 253, DATE_FORMAT(NOW(), '%Y-01-01 00:00:00') FROM gold_log WHERE nick='PrestonConnors';
+----------------+---+---+-----+-----------------------------------------+
| nick | 0 | 0 | 253 | DATE_FORMAT(NOW(), '%Y-01-01 00:00:00') |
+----------------+---+---+-----+-----------------------------------------+
| PrestonConnors | 0 | 0 | 253 | 2015-01-01 00:00:00 |
+----------------+---+---+-----+-----------------------------------------+
1 row in set (0.01 sec)
有人可以帮助将我的 INSERT IGNORE INTO 语句变成一个只INSERT 将一行插入表中并解释我的查询出了什么问题的语句吗？
这是表格的布局：
mysql> describe gold_log;
+-------------------+---------------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------------------+---------------------+------+-----+---------+----------------+
| id | int(10) unsigned | NO | PRI | NULL | auto_increment |
| nick | char(25) | NO | PRI | NULL | |
| amount | decimal(10,4) | YES | MUL | NULL | |
| stream_online | tinyint(1) | NO | MUL | NULL | |
| modification_type | tinyint(3) unsigned | NO | MUL | NULL | |
| dt | datetime | NO | PRI | NULL | |
+-------------------+---------------------+------+-----+---------+----------------+
6 rows in set (0.00 sec)
以下是警告：
mysql> SHOW warnings;
+-------+------+----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+
| Level | Code | Message |
+-------+------+----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+
| Note | 1592 | Unsafe statement written to the binary log using statement format since BINLOG_FORMAT = STATEMENT. INSERT IGNORE... SELECT is unsafe because the order in which rows are retrieved by the SELECT determines which (if any) rows are ignored. This order cannot be predicted and may differ on master and the slave. |
| Note | 1592 | Unsafe statement written to the binary log using statement format since BINLOG_FORMAT = STATEMENT. Statements writing to a table with an auto-increment column after selecting from another table are unsafe because the order in which rows are retrieved determines what (if any) rows will be written. This order cannot be predicted and may differ on master and the slave. |
+-------+------+----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------+
2 rows in set (0.00 sec)
【问题讨论】：
-
在插入运行后，您是否真的看到了多个新行？它们是一样的吗？
-
作为 Darius，我倾向于质疑“受影响”行的数量，这可能会产生误导
-
尝试用一些conatsnt替换
NOW() -
@houssam 我在问题中添加了表格布局。主键是 id 和 nick @DariusX。除了
id列之外，这些行是相同的。 -
警告是什么？在
insert ignore...之后直接输入show warnings以查看它们。
标签： mysql