如何从选择中创建具有给定列名的临时表？答案

【问题标题】：How to create temporary table with given column names from select?如何从选择中创建具有给定列名的临时表？
【发布时间】：2014-05-02 13:16:17
【问题描述】：

如何从 select 中创建具有给定列名的临时表？

我的意思是这样的（我放“as newData”只是为了说明这个想法，这是行不通的）：

 CREATE TEMPORARY TABLE IF NOT EXISTS tmp AS
 SELECT id, min(data) as newData FROM myTable WHERE id > 100 GROUP BY id;

所以我可以得到一个像这样的表：

+-------------------+------------------+------+-----+---------+-------+
| Field             | Type             | Null | Key | Default | Extra |
+-------------------+------------------+------+-----+---------+-------+
| id                | int(10) unsigned | NO   |     | 0       |       |
| newData           | int(10) unsigned | YES  |     | NULL    |       |
+-------------------+------------------+------+-----+---------+-------+

问题是如果我直接建表，第二个字段名包含禁止符号，不知道怎么用：

+-------------------+------------------+------+-----+---------+-------+
| Field             | Type             | Null | Key | Default | Extra |
+-------------------+------------------+------+-----+---------+-------+
| id                | int(10) unsigned | NO   |     | 0       |       |
| min(data)         | int(10) unsigned | YES  |     | NULL    |       |
+-------------------+------------------+------+-----+---------+-------+

【问题讨论】：

标签： mysql temp-tables create-table

【解决方案1】：

as newData 按您的预期工作；

mysql> CREATE TABLE myTable (
  id INT NOT NULL DEFAULT 0,
  data INT
);

mysql> CREATE TEMPORARY TABLE tmp AS
         SELECT id, min(data) as newData FROM myTable WHERE id > 100 GROUP BY id;

mysql> desc tmp;
+---------+---------+------+-----+---------+-------+
| Field   | Type    | Null | Key | Default | Extra |
+---------+---------+------+-----+---------+-------+
| id      | int(11) | NO   |     | 0       |       |
| newData | int(11) | YES  |     | NULL    |       |
+---------+---------+------+-----+---------+-------+
2 rows in set (0.01 sec)

【讨论】：