更新 select 语句中所有条目的表

Question

在我的场景中，我从条件为真的表中选择所有条目，将其放入向量中并通过循环使用更新语句，传递向量的值。它有效。

SELECT * FROM MAP AS A WHERE EXISTS  
(SELECT (X, Y) FROM MAP AS B WHERE B.X = A.X + 1 AND B.Y = A.Y ) AND EXISTS     
(SELECT (X, Y) FROM MAP AS C WHERE C.X = A.X - 1 AND C.Y = A.Y ) ;

for...
UPDATE MAP SET VAL = 2 WHERE X = ? AND Y = ?; 
...

但我想尝试使用单个语句来完成此目标，虽然我们可以使用 select 语句更新表，但在我的场景中，在选择记录之前需要检查 2 个键，所以我不是能够将 x 或 y 的 where 条件放在一起。

UPDATE MAP SET USED = 1 WHERE EXISTS (
SELECT * FROM MAP AS A WHERE EXISTS  
(SELECT (X, Y) FROM MAP AS B WHERE B.X = A.X + 1 AND B.Y = A.Y ) AND EXISTS     
(SELECT (X, Y) FROM MAP AS C WHERE C.X = A.X - 1 AND C.Y = A.Y ) );

当我像上面那样设置 where 存在条件时，它会更新所有条目。如何在一个查询中更新表？

Answer 1

您的子查询的问题在于它没有在 UPDATE 语句中引用表 (MAP)。

只需删除MAP AS A 子查询并直接引用MAP（UPDATE 不允许表别名）：

UPDATE MAP
SET USED = 1
WHERE EXISTS (SELECT 1 FROM MAP AS B WHERE B.X = MAP.X + 1 AND B.Y = MAP.Y)
  AND EXISTS (SELECT 1 FROM MAP AS C WHERE C.X = MAP.X - 1 AND C.Y = MAP.Y)

Answer 2

由于您已验证子查询正在返回您要更新的行，因此您的更新应如下所示：

UPDATE MAP SET USED = 1 
WHERE (X,Y) IN (
SELECT X, Y FROM MAP AS A WHERE EXISTS  
(SELECT X, Y FROM MAP AS B WHERE B.X = A.X + 1 AND B.Y = A.Y ) AND EXISTS     
(SELECT X, Y FROM MAP AS C WHERE C.X = A.X - 1 AND C.Y = A.Y ) );