Oracle 行到列

Question

我有一个包含以下列和 2 行的表格：

COL1,COL2,COL3,NAME,DATE

两行中COL1、COL2、COL3的值为A、B、C。第一行中 NAME 的值是“DEL”，第二行是“LAP”。第一行 DATE 的值是“11.12.13”，第二行是“13.11.13”。

现在我想要一个包含单行和以下列的视图

COL1,COL2,COL3,DEL,LAP with values A,B,C,11.12.13,13.11.13.

是否可以通过枢轴或任何其他功能实现

谢谢

Answer 1

SQL Fiddle

Oracle 11g R2 架构设置：

CREATE TABLE table_name (COL1,COL2,COL3,N_NAME,D_DATE) AS 
          SELECT  'A','B','C', 'DEL', '11.12.13' FROM DUAL
UNION ALL SELECT  'A','B','C', 'LAP', '13.11.13' FROM DUAL
UNION ALL SELECT  'A','B','C', 'DEL', '12.12.13' FROM DUAL
UNION ALL SELECT  'A','B','C', 'LAP', '14.11.13' FROM DUAL;

查询 1：

如果COL1、COL2、COL3 和N_Name 的组合是唯一的，那么您可以这样做：

SELECT Col1,
       Col2,
       Col3,
       MIN( CASE N_Name WHEN 'DEL' THEN D_Date END ) AS DEL,
       MIN( CASE N_Name WHEN 'LAP' THEN D_Date END ) AS LAP
FROM   table_name
GROUP BY
       Col1,
       Col2,
       Col3

Results：

| COL1 | COL2 | COL3 |      DEL |      LAP |
|------|------|------|----------|----------|
|    A |    B |    C | 11.12.13 | 13.11.13 |

查询 2：

但是，如果您可以有多个行具有相同的 COL1、COL2、COL3 和 N_Name 组合，并且您希望所有行都返回（按日期顺序），那么您可以这样做：

WITH indexed_data AS (
  SELECT Col1,
         Col2,
         Col3,
         N_Name,
         D_Date,
         ROW_NUMBER() OVER ( PARTITION BY Col1, Col2, Col3, N_Name ORDER BY D_Date ) AS idx
  FROM   table_name  
)
SELECT Col1,
       Col2,
       Col3,
       MIN( CASE N_Name WHEN 'DEL' THEN D_Date END ) AS DEL,
       MIN( CASE N_Name WHEN 'LAP' THEN D_Date END ) AS LAP
FROM   indexed_data
GROUP BY
       Col1,
       Col2,
       Col3,
       idx
ORDER BY
       Col1,
       Col2,
       Col3,
       idx

Results：

| COL1 | COL2 | COL3 |      DEL |      LAP |
|------|------|------|----------|----------|
|    A |    B |    C | 11.12.13 | 13.11.13 |
|    A |    B |    C | 12.12.13 | 14.11.13 |

Answer 2

with tab (COL1,COL2,COL3,N_NAME,D_DATE) as ( 
select  'A','B','C', 'DEL', '11.12.13' from dual union all
select  'A','B','C', 'LAP', '13.11.13' from dual)
select COL1, COL2, COL3, 
       min(decode(N_NAME, 'DEL', D_DATE, NULL)) DEL,
       min(DECODE(N_NAME, 'LAP', D_DATE, NULL)) LAP
from tab
group by COL1, COL2, COL3 

输出

| COL1 | COL2 | COL3 |      DEL |      LAP |
|------|------|------|----------|----------|
|    A |    B |    C | 11.12.13 | 13.11.13 |

Answer 3

假设两行的公共字段是COL1、COL2和COL3。

SELECT a.col1, 
       a.col2, 
       a.col3, 
       a.date AS DEL, 
       b.date AS LAP 
FROM   yourtable AS a 
       INNER JOIN yourtable AS b 
               ON a.col1 = b.col1 
                  AND a.col2 = b.col2 
                  AND a.col3 = b.col3 
                  AND a.name = 'DEL' 
                  AND b.name = 'LAP'