从 Treeview Nod 反向跟踪 XMLNode答案

【问题标题】：Reverse tracking a XMLNode from a Treeview Nod从 Treeview Nod 反向跟踪 XMLNode
【发布时间】：2010-10-29 11:45:39
【问题描述】：

我已将 XMLNodeList 及其子节点集合分配给 Treeview.. 我可以看到树视图上的所有数据..

现在我选择一个树视图节点项。我现在想要获取与之关联的 XMLNode。基本上我想要从 TreeNode ---> XMLNode 进行转换这可能吗？

【问题讨论】：

标签： .net xml

【解决方案1】：

using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Text;
using System.Windows.Forms;
using System.Xml;

namespace XmlIntrospection
{
    public partial class Form1 : Form
    {
        public class XmlNodeTree : TreeNode
        {
            private XmlNode mNode;
            public XmlNode Node
            {
                get { return mNode; }
            }

            public XmlNodeTree(XmlNode node)
            {
                mNode = node;
                if (node.NodeType == XmlNodeType.Text)
                {
                    Text = node.InnerText;
                }
                else
                {
                    Text = node.Name;
                }

                if (node.Attributes != null)
                {
                    foreach (XmlAttribute a in node.Attributes)
                    {
                        Text += " " + a.OuterXml;
                    }
                }
            }
        }

        private XmlDocument doc;

        public Form1()
        {
            InitializeComponent();
            doc = new XmlDocument();
        }

        /// <summary>
        /// Fill the tree View with xml Node recurcively
        /// </summary>
        /// <param name="c"> current Tree node </param>
        /// <param name="l"> current xml node </param>
                private void FillTreeView(TreeNodeCollection c,XmlNodeList l)
                {
                    if (l == null)
                    {
                        return;
                    }

                    foreach (XmlNode e in l)
                    {
                        XmlNodeTree n = new XmlNodeTree(e);
                        c.Add(n);
                        FillTreeView(n.Nodes, e.ChildNodes);
                    }
                }

        private void Init()
        {
            treeView1.Nodes.Clear();
            textBox1.Text = "";
        }


        private void openToolStripMenuItem_Click(object sender, EventArgs e)
        {
            if (openFileDialog1.ShowDialog() == DialogResult.OK)
            {
                try
                {
                    Init();
                    doc.Load(openFileDialog1.FileName);
                    XmlNodeTree root = new XmlNodeTree(doc.LastChild);
                    textBox1.Text = doc.InnerXml;
                    treeView1.Nodes.Add(root);
                    FillTreeView(root.Nodes,doc.LastChild.ChildNodes);
                }
                catch
                {
                    MessageBox.Show("File " + openFileDialog1.FileName + " no valid xml file");
                }
            }
        }

        private void treeView1_AfterSelect(object sender, TreeViewEventArgs e)
        {
           XmlNodeTree currentNode = (XmlNodeTree) e.Node;
           propertyGrid1.SelectedObject = currentNode.Node;
        }       
    }
}

【讨论】：