如何在php中通过id调用rest api？ [关闭]

Question

现在我可以输出http://localhost/posts/

[
  {
    "id": "1",
    "title": "first post",
    "description": "here my first post",
    "status": "Y"
  },
  {
    "id": "2",
    "title": "second post",
    "description": "here my second post",
    "status": "Y"
  }
]

这里是我的源代码

if ($_SERVER['REQUEST_METHOD'] == "GET"){
    @List($objnm, $objid) = explode('/', $_GET['url']);
    if ($objnm == 'posts')
    {
        $post = $db->query('SELECT * FROM post WHERE status="Y"');
        echo json_encode($post, JSON_PRETTY_PRINT);
    }
    else
    {
        http_response_code(401);
    }

}

我的 htaccess

RewriteEngine On
RewriteRule ^([^/]+)/? index.php?url=$1 [L,QSA]

我需要http://localhost/posts/1 的输出 谁能帮帮我？

Answer 1

我会建议使用 is_numeric() 函数来检查第二个参数是否为数字。

if ($_SERVER['REQUEST_METHOD'] == "GET"){
    @List($objnm, $objid) = explode('/', $_GET['url']);
    if ($objnm == 'posts')
    {
        if(is_numeric($objid)) {
            $post = $db->query('SELECT * FROM post WHERE status="Y" AND id="'.$objid.'";');
            echo json_encode($post, JSON_PRETTY_PRINT);
        }
        else 
        {
            $post = $db->query('SELECT * FROM post WHERE status="Y"');
            echo json_encode($post, JSON_PRETTY_PRINT);
        }
    }
    else
    {
        http_response_code(401);
    }

}