【发布时间】:2016-10-06 14:39:28
【问题描述】:
我应该如何继续将std::chrono::minutes::rep 类型值转换为小时表示。
#include <iostream>
#include <chrono>
using namespace std;
using namespace std::chrono;
int main() {
minutes::rep time = 4;
std::cout << time; // outputs as minutes, need in hours
// duration cast doesn't seems to work here because it
// needs minutes instead of minutes::rep probably
return 0;
}
【问题讨论】:
-
您为什么使用
minutes::rep而不仅仅是minutes? -
<chrono>教程:youtube.com/watch?v=P32hvk8b13M
标签: c++ linux date c++11 chrono