Python 中的石头、剪子、剪刀、斯波克、蜥蜴，玩家 2 自动获胜

Question

对于一个练习，我们需要重现大爆炸理论成员所玩的游戏：Rock、Paper、Scissor、Spock、Lizard。我设法几乎完全重新创建它，唯一的问题是：玩家 2 自动获胜。有人可以告诉我需要在哪里更改代码并解释原因吗？

import sys

t = len(sys.argv)

if(t < 2 or t > 3):
    print("Usage: rpsls.py symbool1 symbool2")
    exit()
i = 1
while (i > 0):
    a = sys.argv[1]
    b = sys.argv[2]
    a = a.lower()
    b = b.lower()
    if(a != "rock" and a != "paper" and a != "scissor" and a != "lizard" and a != "spock"):
        print("What's that? please use a real symbol!")

    elif(b != "rock" and b != "paper" and b != "scissor" and b != "lizard" and b != "spock"):
        print("What's that? please use a real symbol!")

    else:
        if (a == "paper" and b == "scissor"):
            s = True
            i = 0
        else:
            s = False
            i = 0
        if(a == "paper" and b == "rock"):
            s = True
            i = 0
        else:
            s = False
            i = 0
        if(a == "rock" and b == "lizard"):
            s = True
            i = 0
        else:
            s = False
            i = 0
        if(a == "lizard" and b == "spock"):
            s = True
            i = 0
        else:
            s = False
            i = 0
        if(a == "spock" and b == "scissors"):
            s = True
            i = 0
        else:
            s = False
            i = 0
        if(a == "scissor" and b == "lizard"):
            s = True
            i = 0
        else:
            s = False
            i = 0
        if(a == "lizard" and b == "paper"):
            s = True
            i = 0
        else:
            s = False
            i = 0
        if(a == "paper" and b == "spock"):
            s = True
            i = 0
        else:
            s = False
            i = 0
        if(a == "spock" and b == "rock"):
            s = True
            i = 0
        else:
            s = False
            i = 0
        if(a == "rock" and b == "scissor"):
            s = True
            i = 0
        else:
            s = False
            i = 0
        if(a == b):
            print("It's a tie!")
            i = 0
            exit()

if(s == True):
        print("Player 1 wins!")
if(s == False):
        print("Player 2 wins!")

Answer 1

您的每个 if 语句都有一个 else。只有一个 if 语句可以为真，这意味着所有其他 else 语句都被评估。结果是最后一个 else 语句（将 s 设置为 False）将“获胜”，因此玩家 2 获胜。

您应该删除所有 else 语句，并将代码重组为一系列 if...elif... 块：

   if a == "paper" and b == "scissor":
        s = True
        i = 0
   elif a == "paper" and b == "rock":

（注意，如果条件不需要括号。）