【发布时间】:2026-02-22 03:35:01
【问题描述】:
所以我有一个基本的猜数字游戏。
在我的int main 中,我有三个函数用来播放它。我有一个围绕这些函数的游戏循环,bool = false 和 return value 设置为等于我的 PlayAgain 函数。
一切运行良好,但当你猜对了数字时,它会询问你是否出于某种原因想再玩两次。
我已尝试删除我在 main 中调用该函数的实例之一:
#include <iostream>
#include <cstdlib>
#include <ctime>
#include<string>
void PrintIntro();
void PlayGame();
bool PlayAgain();
int main() {
bool bPlayAgain = false;
do {
PrintIntro();
PlayGame();
PlayAgain(); //I've tried removing this line
bPlayAgain = PlayAgain(); //I've also played around with this one
} while (bPlayAgain);
return (0);
}
void PrintIntro()
{
std::cout << "Guess a number between 1-100, fool!\n";
}
void PlayGame()
{
srand(static_cast<unsigned int> (time(0)));
int HiddenNumber = rand();
int Number = (HiddenNumber % 100) + 1;
int Guess;
do {
std::cin >> Guess;
if (Guess > Number) {
std::cout << "You are too high bro!\n\n";
}
else if (Guess < Number) {
std::cout << "You need to get higher bro!\n\n";
}
else if (Guess = Number) {
std::cout << "You are just high enough, you win!\n\n";
}
} while (Guess != Number);
}
bool PlayAgain()
{
std::string Response = "";
std::cout << "Would you like to play again? yes or no." << std::endl;
std::getline(std::cin, Response);
std::cout << std::endl;
return (Response[0] == 'y') || (Response[0] == 'Y');
}
【问题讨论】:
-
欢迎来到 Nicholas 社区。尽管您在询问之前似乎已经对此进行了一些研究,但我鼓励您继续调试您的代码。这很可能是一个简单的错误(调用 PlayAgain 方法的次数超出预期),而 * 确实不是提供此类调试帮助的正确网站。
-
"
//I've tried removing this line" 肯定需要删除。 -
我相信代码
PlayAgain(); bPlayAgain = PlayAgain();调用了两次函数?如果您尝试删除其中一个,我不明白您的文字。
标签: c++ boolean return-value