如何从 Mysql 数据库中获取 2 列数据并将其转换为 csv 文件

Question

好的，所以我正在尝试为我的网站创建一个电子邮件通讯注册，并且我创建的文件用于从我的数据库中获取名为 Name 和 Email 的 2 列，而不仅仅是保存像我想要的那样将这两列转换为 csv。相反，它保存了整个表。我对自己做错了什么感到困惑。任何帮助表示赞赏这里是代码。

<?php

function exportMysqlToCsv($table,$filename = 'export.csv')
{
    $csv_terminated = "\n";
    $csv_separator = ",";
    $csv_enclosed = '"';
    $csv_escaped = "\\";
    $sql_query = "select `Name`, `Email` from $table";

    // Gets the data from the database
    $result = mysql_query($sql_query);
    $fields_cnt = mysql_num_fields($result);


    $schema_insert = '';

    for ($i = 0; $i < $fields_cnt; $i++)
    {
        $l = $csv_enclosed . str_replace($csv_enclosed, $csv_escaped . $csv_enclosed,
            stripslashes(mysql_field_name($result, $i))) . $csv_enclosed;
        $schema_insert .= $l;
        $schema_insert .= $csv_separator;
    } // end for

    $out = trim(substr($schema_insert, 0, -1));
    $out .= $csv_terminated;

    // Format the data
    while ($row = mysql_fetch_array($result))
    {
        $schema_insert = '';
        for ($j = 0; $j < $fields_cnt; $j++)
        {
            if ($row[$j] == '0' || $row[$j] != '')
            {

                if ($csv_enclosed == '')
                {
                    $schema_insert .= $row[$j];
                } else
                {
                    $schema_insert .= $csv_enclosed . 
                    str_replace($csv_enclosed, $csv_escaped . $csv_enclosed, $row[$j]) . $csv_enclosed;
                }
            }
            else
            {
                $schema_insert .= '';
            }

            if ($j < $fields_cnt - 1)
            {
                $schema_insert .= $csv_separator;
            }
        } // end for

        $out .= $schema_insert;
        $out .= $csv_terminated;
    } // end while

    header("Cache-Control: must-revalidate, post-check=0, pre-check=0");
    header("Content-Length: " . strlen($out));
    // Output to browser with appropriate mime type, you choose ;)
    header("Content-type: text/x-csv");
    //header("Content-type: text/csv");
    //header("Content-type: application/csv");
    header("Content-Disposition: attachment; filename=$filename");
    echo $out;
    exit;

}

?>

Answer 1

使用以下函数并将其字段作为数组传递：

 function arrayToCsv( array &$fields, $delimiter = ';', $enclosure = '"', $encloseAll =    false, $nullToMysqlNull = false ) {
   $delimiter_esc = preg_quote($delimiter, '/');
   $enclosure_esc = preg_quote($enclosure, '/');

   $output = array();
   foreach ( $fields as $field ) {
      if ($field === null && $nullToMysqlNull) {
        $output[] = 'NULL';
        continue;
    }

    // Enclose fields containing $delimiter, $enclosure or whitespace
    if ( $encloseAll || preg_match( "/(?:${delimiter_esc}|${enclosure_esc}|\s)/", $field ) ) {
        $output[] = $enclosure . str_replace($enclosure, $enclosure . $enclosure, $field) . $enclosure;
    }
    else {
        $output[] = $field;
    }
}

return implode( $delimiter, $output );
}