在一个查询中比较两个不同的查询输出答案

【问题标题】：compare two different output of queries in one query在一个查询中比较两个不同的查询输出
【发布时间】：2014-08-14 05:46:21
【问题描述】：

我有两个相互连接的表主键 - 外键。我想检查他们的输出是否匹配。

查询 ::

Select LINK_ID as A1, PHYSICAL_NUM_LANES as count1 from RDF_NAV_LINK where PHYSICAL_NUM_LANES is not null

RecNo    | A1           | count1
-----------------------------------
1        |51364636      |2
2        |51366793      |1
3        |51366795      |1
4        |51366796      |4

查询 ::

Select LINK_ID as A2, count(*) as count2 from RDF_LANE Group by LINK_ID

RecNo   |A2         |count2
----------------------------------
1       |51364636   |2
2       |51366793   |2
3       |53676455   |3
4       |53676460   |1

现在我想检查 A1 = A2 那么 count1 是否必须等于 count2 （如果不是我的输出）

【问题讨论】：

标签： mysql sql sqlite

【解决方案1】：

在A1 = A2 AND count1 <> count2 上加入您的两个选择

SELECT * FROM
(Select LINK_ID as A1, PHYSICAL_NUM_LANES as count1 from RDF_NAV_LINK where PHYSICAL_NUM_LANES is not null) X
INNER JOIN
(Select LINK_ID as A2, count(*) as count2 from RDF_LANE Group by LINK_ID) Y
ON A1 = A2 AND count1 <> count2;

【讨论】：

【解决方案2】：

这样试试

SELECT *
FROM
(
  (
   Select LINK_ID AS A1, PHYSICAL_NUM_LANES AS Count1 
   FROM RDF_NAV_LINK 
   WHERE PHYSICAL_NUM_LANES IS NOT NULL
  )S JOIN
  (
   Select LINK_ID AS A2, Count(*) As Count2 
   FROM RDF_LANE 
   GROUP BY LINK_ID
  )T ON T.A1 = S.A1 AND T.Count2 <> S.Count1
) Tmp

【讨论】：