【发布时间】:2015-10-05 17:57:55
【问题描述】:
我正在尝试从garage_list:account_id 获取计数
从那里获取1个实例并获取相应的player_list:account_id
还有garage_list:tank_id 到tank_list:tank_id
结束表将如下所示:
tank :: count(玩家人数的替代文字)
IS-3 :: 2 -->(玩家 1,玩家 3)
E-100 :: 3 --> (player1, player 4, player 9)
Select Count(Distinct tank_id) As
counttanks ,
Count(tank_id) As
counttanks ,
tank_id As tank_id From garage_list
RIGHT JOIN player_list
ON player_list.account_id = garage_list.account_id
RIGHT JOIN tank_list
ON player_list.tank_id = tank_list.tank_id
Group By tank_id
where tank_list.level='8',
and player_list.clan='BAD-1'
and player_list.account_id = '500549663'
TABLES
<garage_list>
account_id :: tank_id
1234 :: 20
1234 :: 44
4321 :: 18
<tank_list>
Tank_id :: name :: long_name :: row1 :: row2 :: row3 ::
20 :: sherman::usa_sher
<player_list>
account_id :: clan :: nickname
1234 ::bad-1:: joker
4321 ::bad-g :: grumpy
【问题讨论】:
-
你想要你的播放器列表是垂直的还是水平的?
-
它将是垂直的,因为取决于级别的选项,我最终可能会得到 60 个奇怪的结果
-
您的最终结果与提供的样本数据不符。
标签: sql right-join