看起来您要经历很多事情才能获得一点...我会从一个查询开始,以每天获取最小和最大人员,然后从那里开始。我想要一个关于用户日志时间戳的索引...
select
LogInOut.LogActivity,
LogInOut.JustDay,
LogInOut.What_Time,
ULMain.UserLog_User_ID,
U1.user_name
from
( select
day( UL.UserLog_Timestamp ) as JustDay,
max( UL.UserLog_Log_type ) as LogActivity,
min( UL.userlog_timestamp ) as What_Time
from
UserLog UL
where
UL.UserLog_Log_Type = 1
group by
day( UL.UserLog_Timestamp )
UNION
select
day( UL.UserLog_Timestamp ) as JustDay,
max( UL.UserLog_Log_type ) as LogActivity,
max( UL.userlog_timestamp ) as What_Time
from
UserLog UL
where
UL.UserLog_Log_Type = 2
group by
day( UL.UserLog_Timestamp ) ) LogInOut
JOIN UserLog ULMain
on LogInOut.What_Time = ULMain.UserLog_Timestamp
AND LogInOut.LogActivity = ULMain.UsrLog_Log_Type
JOIN Users U1
on ULMain.UserLog_User_ID = U1.User_ID
order by
LogInOut.JustDay,
LogInOut.LogActivity
会创建类似的东西
LogActivity JustDay What_Time UserLog_User_ID user_name
1 Mar 1 7:56am 123 Bill Board
2 Mar 1 6:23pm 431 Eilean Dover
1 Mar 2 7:02am 98 Crystal Clear
2 Mar 2 6:47pm 221 Ben Dover
现在,如果您希望将其汇总为单行(交叉表),以便一行显示当天,谁在第一个,谁最后一个,我将更改顶部并通过类似的方式添加一个组
select
LogInOut.JustDay,
MIN( LogInOut.What_Time ) as EarlyLogin,
MAX( IF( LogInOut.LogActivity = 1, U1.User_Name, ' ' )) as EarlyUser,
MAX( LogInOut.What_Time ) as LastLogOut
MAX( IF( LogInOut.LogActivity = 2, U1.User_Name, ' ' )) as LastUser
from
(exact rest of from / join / order by clause)
group by
LogInOut.JustDay
JustDay EarlyLogin EarlyUser LastLogOut LastUser
Mar 1 7:56am Bill Board 6:23pm Eilean Dover
Mar 2 7:02am Crystal Clear 6:47pm Ben Dover