【发布时间】：2013-05-19 14:02:16
【问题描述】：
我有一个搜索页面，允许用户使用按省、区或村搜索来搜索
如果用户按省选择浏览器显示正确答案
但是如果用户选择省和区，系统会改变它显示相同的结果
治理
- governorate_id
- governorate_name 区
- 区号
- 区名
- governorate_id
村庄
- 身份证
- 村名
- 区号
成员 user_id
- governorate_id
- 区号
- village_id
我希望当用户选择其中一种类型或所有系统时必须显示与选择相关的用户列表而不是所有用户
代码：
$errorMSG = "";
$outputlist = "";
//**********search by locationn***************************************//
if(isset($_POST['listbyq']))
{
//********************by governorate**************************************//
if($_POST['listbyq']=="by_gov")
{
$bygov = $_POST['governorate'];
@ $bydist = $_POST['district'];
@ $byvillage = $_POST['village'];
echo $bygov;
echo $bydist;
echo $byvillage;
$sql = mysql_query("SELECT user_id,first_name, last_name, birth_date, registered_date,
s.specialization_name,
g.governorate_name,
d.district_name,
v.village_name
FROM members u
INNER JOIN specialization s
ON u.specialization = s.specialization_id
INNER JOIN governorate g
ON u.governorate = g.governorate_id
INNER JOIN districts d
ON u.district = d.district_id
INNER JOIN village v
ON u.village = v.id
where ($bygov = '' or governorate = '$bygov') and
($bydist = '' or district = '$bydist') and
($byvillage = '' or village = '$byvillage')")
or die(mysql_error());
$num_row = mysql_num_rows($sql);
if($num_row > 0 )
{
while($row = mysql_fetch_array($sql))
{
$row_id = $row['user_id'];
$row_first_name = $row['first_name'];
$row_last_name = $row['last_name'];
$row_birthdate = $row['birth_date'];
$row_registered_date = $row['registered_date'];
$row_spec = $row['specialization_name'];
$row_gov = $row['governorate_name'];
$row_dist = $row['district_name'];
$row_village = $row['village_name'];
////***********for the upload image*************************//
$check_pic="members/$row_id/image01.jpg";
$default_pic="members/0/image01.jpg";
if(file_exists($check_pic))
{
$user_pic="<img src=\"$check_pic\"width=\"120px\"/>";
}
else
{
$user_pic="<img src=\"$default_pic\"width=\"120px\"/>";
}
$outputlist.='
<table width="100%">
<tr>
<td width="23%" rowspan="5"><div style="height:120px;overflow:hidden;"><a href = "http://localhost/newadamKhoury/profile.php?user_id='.$row_id.'" target="_blank">'.$user_pic.'</a></div></td>
<td width="14%"><div align="right">Name:</div></td>
<td width="63%"><a href = "http://localhost/newadamKhoury/profile.php?user_id='.$row_id.'" target="_blank">'.$row_first_name.' '.$row_last_name.'</a></td>
</tr>
<tr>
<td><div align="right">Birth date:</div></td>
<td>'.$row_birthdate.'</td>
</tr>
<tr>
<td><div align="right">Registered:</div></td>
<td>'.$row_registered_date.'</td>
</tr>
<tr>
<td><div align="right">Job:</div></td>
<td>'.$row_spec.'</td>
</tr>
<tr>
<td><div align="right">Location:</div></td>
<td>'.$row_gov.'__'.$row_dist.'__'.$row_village.'</td>
</tr>
</table>
<hr />
';
}
}
}
else
{
$errorMSG = "No member within this selected governorate";
}
}
【问题讨论】：
标签： php mysql inner-join