【发布时间】:2018-11-01 03:30:48
【问题描述】:
鉴于我有如下表格:
时间表
+-------+------------+--------+----------------+-------+---------+
| index | date | empid | dept | sfrom | slength |
+-------+------------+--------+----------------+-------+---------+
| 0 | 09-24-2018 | 943023 | RADIOLOGY | 03PM | 8 |
| 1 | 09-24-2018 | 891046 | SURGERY | 07AM | 8 |
| 2 | 09-24-2018 | 878397 | RADIOLOGY | 11PM | 8 |
| 3 | 09-24-2018 | 886190 | CARDIOLOGY | 03PM | 8 |
| 4 | 09-24-2018 | 878397 | RADIOLOGY | 11PM | 8 |
| 5 | 09-24-2018 | 891330 | SURGERY | 03PM | 8 |
| 6 | 09-24-2018 | 995561 | SURGERY | 11PM | 8 |
| 7 | 09-24-2018 | 967577 | MATERNITY | 03PM | 8 |
| 8 | 09-24-2018 | 913891 | PEDIATRICS | 03PM | 8 |
| 9 | 09-24-2018 | 939148 | EMERGENCY | 07AM | 8 |
| 10 | 09-24-2018 | 995636 | RADIOLOGY | 11PM | 8 |
| 11 | 09-24-2018 | 995561 | EMERGENCY | 11PM | 8 |
| 12 | 09-24-2018 | 967577 | SURGERY | 07AM | 8 |
| 13 | 09-24-2018 | 883069 | INTENSIVE CARE | 07AM | 8 |
| 14 | 09-24-2018 | 951876 | ONCOLOGY | 03PM | 8 |
| 15 | 09-24-2018 | 884866 | CARDIOLOGY | 07AM | 8 |
| 16 | 09-24-2018 | 864425 | ONCOLOGY | 03PM | 8 |
员工表
+-------+--------+------------+-----------+---------+----------------+----------------+------+
| index | empid | lastName | firstName | emptype | cellphone | homephone | ftpt |
+-------+--------+------------+-----------+---------+----------------+----------------+------+
| 0 | 919675 | Cermak | Vern | LPN | (138)7198-0862 | (655)2249-9926 | FT |
| 1 | 906704 | Paille | Lorilee | NULL | (858)1100-2722 | (377)1506-1986 | PT |
| 2 | 900486 | Ober | Shalanda | NULL | (210)1508-8132 | (820)1612-0197 | FT |
| 3 | 883367 | Clyburn | Jeffry | LPN | (420)7798-7220 | (476)7661-3070 | FT |
| 4 | 953807 | Quarles | Timmy | LPN | (513)2756-9892
如果我必须计算每个员工类型和每个班次的每个部门的总成本,我应该如何在 sql 中执行此操作?
如果轮班包括午夜,我的工资乘以 25%?
我有如下示例输出,但不知道如何执行此操作?:
+------------+---------------+----------------+---------+
| DEPARTMENT | EMPLOYEE_TYPE | SHIFT | COST |
+------------+---------------+----------------+---------+
| Anesthesia | LPN | 7 AM –3 | $24,567 |
| Anesthesia | LPN | 3 PM –11PM | $18,546 |
| Anesthesia | LPN | 11 PM –7AM | $22,874 |
| Anesthesia | NA | 7 AM –3 PM | $9,764 |
| Anesthesia | NA | 3 PM –11 PM | $10,287 |
| Anesthesia | NA | 11 PM –7 AM | $6, 875 |
| Anesthesia | RN | 7 AM –3 PM | $33,123 |
+------------+---------------+----------------+---------+
这是我到现在为止的 sql 语句: 但是我应该如何让它工作呢? 编辑1:
Select
t1.dept,
t2.emptype,
t1.sfrom,
t1.slength,
SUM(t1.slength) as hours
CASE WHEN CAST(STR_TO_DATE(sfrom,'%h%p') +
STR_TO_DATE(slength,'%H')) > STR_TO_DATE(23,'%H')
then (slength*10*1.25) else (slength*10) end as cost
from
schedule_2 as t1
Join (select
empid,
emptype
from
employees_2) as t2 ON t1.empid=t2.empid
GROUP BY
dept,
emptype,
slength;
EDIT2:
Select
t1.dept,
t2.emptype,
t1.sfrom,
t1.slength,
SUM(t1.slength) as hours
CASE WHEN HOUR(STR_TO_DATE(sfrom,'%h%p') +
STR_TO_DATE(slength,'%H')) > 23
then (slength*10*1.25) else (slength*10)
from
schedule_2 as t1
Join (select
empid,
emptype
from`
employees_2) as t2 ON t1.empid=t2.empid
GROUP BY
dept,
emptype,
slength;
我收到以下错误,但似乎无法弄清楚原因?
您的 SQL 语法有错误;检查手册 对应于您的 MariaDB 服务器版本,以便使用正确的语法 'CASE WHEN HOUR(STR_TO_DATE(sfrom,'%h%p') + STR_TO_DATE(slength,'%H')) > 23 然后 ' 在第 2 行
【问题讨论】:
-
到目前为止你有tried anything吗?
-
是的,我正在尝试将两个表连接在一起,然后进行分组,但仍然无法执行它。我是 sql 新手:/
-
您也可以包含您的查询吗?
-
每小时的工资或价格在哪里?我在任何桌子上都没有看到它...
-
您只是在
case语句中错过了逗号附近.. 当进行查询时,使您的查询可读.. 它会帮助您找到错字或缺失.. 当然还有美丽..跨度>