【发布时间】:2009-08-26 13:36:41
【问题描述】:
精确地使用内连接进行选择,该选择在表之间的多个字段中具有关系
示例:
DataSet dt = new Select().From(SubConta.Schema)
.InnerJoin(PlanoContabilSubConta.EmpSubContaColumn, SubConta.CodEmpColumn)
.InnerJoin(PlanoContabilSubConta.FilSubContaColumn, SubConta.CodFilColumn)
.InnerJoin(PlanoContabilSubConta.SubContaColumn, SubConta.TradutorColumn)
.Where(PlanoContabilSubConta.Columns.EmpContabil).IsEqualTo(cEmp)
.And(PlanoContabilSubConta.Columns.FilContabil).IsEqualTo(cFil)
.And(PlanoContabilSubConta.Columns.Conta).IsEqualTo(cTrad)
.ExecuteDataSet();
但是生成的sql是错误的:
exec sp_executesql N'/* GetDataSet() */ SELECT [dbo].[SubContas].[CodEmp], [dbo].[SubContas].[CodFil], [dbo].[SubContas].[Tradutor], [dbo].[SubContas].[Descricao], [dbo].[SubContas].[Inativa], [dbo].[SubContas].[DataImplantacao]
FROM [dbo].[SubContas]
INNER JOIN [dbo].[PlanoContabilSubContas] ON [dbo].[SubContas].[CodEmp] = [dbo].[PlanoContabilSubContas].[EmpSubConta]
INNER JOIN [dbo].[PlanoContabilSubContas] ON [dbo].[SubContas].[CodFil] = [dbo].[PlanoContabilSubContas].[FilSubConta]
INNER JOIN [dbo].[PlanoContabilSubContas] ON [dbo].[SubContas].[Tradutor] = [dbo].[PlanoContabilSubContas].[SubConta]
WHERE EmpContabil = @EmpContabil0
AND FilContabil = @FilContabil1
AND Conta = @Conta2
',N'@EmpContabil0 varchar(1),@FilContabil1 varchar(1),@Conta2 varchar(1)',@EmpContabil0='1',@FilContabil1='1',@Conta2='1'
生成这个sql应该怎么做?
exec sp_executesql N'/* GetDataSet() */ SELECT [dbo].[SubContas].[CodEmp], [dbo].[SubContas].[CodFil], [dbo].[SubContas].[Tradutor], [dbo].[SubContas].[Descricao], [dbo].[SubContas].[Inativa], [dbo].[SubContas].[DataImplantacao]
FROM [dbo].[SubContas]
INNER JOIN [dbo].[PlanoContabilSubContas] ON [dbo].[SubContas].[CodEmp] = [dbo].[PlanoContabilSubContas].[EmpSubConta] AND
[dbo].[SubContas].[CodFil] = [dbo].[PlanoContabilSubContas].[FilSubConta] AND
[dbo].[SubContas].[Tradutor] = [dbo].[PlanoContabilSubContas].[SubConta]
WHERE EmpContabil = @EmpContabil0
AND FilContabil = @FilContabil1
AND Conta = @Conta2
',N'@EmpContabil0 varchar(1),@FilContabil1 varchar(1),@Conta2 varchar(1)',@EmpContabil0='1',@FilContabil1='1',@Conta2='1'
【问题讨论】:
标签: subsonic inner-join