订购两个 meged 查询

Question

我有Customers 表，我想提取最短和最长的客户姓名

我是这样做的：

(SELECT TOP 1 CustomerName, LEN(CustomerName) AS LENGTH FROM Customers ORDER BY LEN(CustomerName) ASC, CustomerName ASC)
UNION
(SELECT TOP 1 CustomerName, LEN(CustomerName) AS LENGTH FROM Customers ORDER BY LEN(CustomerName) DESC, CustomerName ASC)

我得到两个正确的结果，但现在我想按LENGTH 列对它们进行排序。我试过这个：

SELECT * FROM
(
(SELECT TOP 1 CustomerName, LEN(CustomerName) AS LENGTH FROM Customers ORDER BY LEN(CustomerName) ASC, CustomerName ASC)
UNION
(SELECT TOP 1 CustomerName, LEN(CustomerName) AS LENGTH FROM Customers ORDER BY LEN(CustomerName) DESC, CustomerName ASC)
)
ORDER BY LEN(CustomerName) ASC

但它给了我这个错误：Syntax error in JOIN operation.

我该怎么做？

Answer 1

select customername,len(customername) as namelength
from (SELECT MAX(LEN(CustomerName)) AS MAXLENGTH, MIN(LEN(CustomerName)) AS MINLENGTH 
      FROM Customers) lens
join customers c on c.len(customername) = lens.maxlength or c.len(customername) = lens.minlength
order by namelength desc, customername