SQL Server - 需要查询工资大于平均工资和小于每个办公室经理的工资

Question

我有两张这样的桌子..

CREATE TABLE Branch
(
    branchID int,
    b_location varchar(50),
    b_contactNo int,

    CONSTRAINT PK_Branch PRIMARY KEY (branchID)
);   

CREATE TABLE Staff
(
    staffID int,
    fullName varchar(100) NOT NULL,
    s_category varchar(25),
    s_email varchar(50),
    s_contactNo int,
    speciality varchar(100),
    qualifications varchar(250),
    pre_employment varchar(200),
    salary numeric(8,2),
    staff_gender char(1),
    staff_joined_date datetime,
    branch_allocated int,

    CONSTRAINT PK_Staff PRIMARY KEY (staffID),

    CONSTRAINT FK_Staff_Branch 
        FOREIGN KEY (branch_allocated) REFERENCES Branch(branchID) ON DELETE CASCADE,

    CONSTRAINT CHK_StaffGender CHECK (staff_gender='M' OR staff_gender='F'),
    CONSTRAINT CHK_FullName CHECK (fullName NOT LIKE '%[^A-Za-z ]%'),
    CONSTRAINT CHK_SALARY CHECK (salary>0 AND salary<=150000)
);

员工表有这个样本数据：

 7 | Nick Carter   | Nurse          | nick@mail.com   | 32145657 | N/A | N/A | 5 Years in London General |  99000.00 | M | 2013-01-04 10:00:00.000 | 1
 8 | Brian OConner | Nurse          | brian@mail.com  | 32678579 | N/A | N/A | 3 Years in London General |  83000.00 | M | 2015-01-09 10:00:00.000 | 2
12 | Jayden Smith  | Office Manager | jayden@mail.com |  5678755 | N/A | N/A | N/A                       | 145000.00 | M | 2013-01-04 10:00:00.000 | 1
13 | Will Smith    | Office Manager | will@mail.com   | 12345678 | N/A | N/A | N/A                       | 135000.00 | M | 2013-01-04 10:00:00.000 | 2

我想找出每个分支机构高于平均工资且低于每个分支机构办公室经理的员工工资

我已经写了一些查询。但不知道如何继续。

SELECT 
    s.staffId AS ID, s.fullName AS Name, s.s_category AS Category, s.salary AS Salary, b.branchId AS 'Branch No'
FROM 
    Staff s 
INNER JOIN 
    Branch b ON s.branch_allocated = b.branchID
WHERE 
    salary > (SELECT AVG(salary) FROM Staff)

WITH tempTable AS 
(
    SELECT DISTINCT branch_allocated, AVG(salary) AS AVG_SAL 
    FROM Staff
    GROUP BY branch_allocated
)
SELECT AVG_SAL 
FROM tempTable

Answer 1

更改您的 WHERE 查询

WHERE 
    salary > ( SELECT AVG(salary) 
               FROM   Staff x 
               WHERE  x.branch_allocated = s.branch_allocated )
AND
    Salary < ( SELECT MIN(salary) 
               FROM   Staff x 
               WHERE  x.s_category = 'Office Manager' ) 

Answer 2

SELECT s.staffId AS ID, 
       s.fullName AS Name, 
       s.s_category AS Category, 
       s.salary AS Salary, 
       b.branchId AS 'Branch No'
FROM Staff s 
INNER JOIN Branch b 
ON s.branch_allocated = b.branchID
WHERE salary > ( SELECT AVG(salary) 
           FROM   Staff x 
           WHERE  x.branch_allocated = s.branch_allocated )
AND salary < (SELECT MIN(salary) FROM Staff  
          where speciality ='Office Manager' Group by branch_allocated)

Answer 3

with empavgsal as(
SELECT s.staffId AS ID, s.fullName AS Name, s.s_category AS Category, s.salary AS Salary, b.branchId AS 'BranchNo' FROM Staff s INNER JOIN Branch b ON s.branch_allocated = b.branchID WHERE s.salary > (SELECT AVG(salary) from Staff Group By s_category where s_category!='Office Manager') 
)
Select e.ID,e.Name,e. Category,e.Salary,e.BranchNo FROM empavgsal INNER JOIN Staff s ON
s.staffId!=e.ID WHERE e.salary<s.s salary AND s.s_category ='Office Manager'