只需使用几个约会技巧。
此代码将为您提供您正在评估的时间的最高点(通过在 SQL 中将自 0 日期以来的小时数相加有效地删除分钟数):
select dateadd(hour, datediff(hour, 0, getdate()), 0)
从那里,您需要一个 CASE 表达式来评估所讨论的时间属于小时的哪个四分位数(这里只是一个 sn-p):
case
when datepart(minute, dtm) > 50 then 60
when datepart(minute, dtm) > 35 then 45
when datepart(minute, dtm) > 20 then 30
when datepart(minute, dtm) > 5 then 15
else 0
end
将这两部分与DATEADD 放在一起,以决定我们要在偶数小时标记上增加多少分钟:
declare @dtms table (dtm datetime);
insert @dtms (dtm)
values ('2019-07-16T12:05:00'),
('2019-07-16T12:06:00'),
('2019-07-16T12:21:00'),
('2019-07-16T12:29:00'),
('2019-07-16T12:35:00'),
('2019-07-16T12:38:00'),
('2019-07-16T12:56:00')
select
dtm,
dateadd(minute,
case
when datepart(minute, dtm) > 50 then 60
when datepart(minute, dtm) > 35 then 45
when datepart(minute, dtm) > 20 then 30
when datepart(minute, dtm) > 5 then 15
else 0
end, dateadd(hour, datediff(hour, 0, dtm), 0)) as rounded
from @dtms;
结果:
+-------------------------+-------------------------+
| dtm | rounded |
+-------------------------+-------------------------+
| 2019-07-16 12:05:00.000 | 2019-07-16 12:00:00.000 |
| 2019-07-16 12:06:00.000 | 2019-07-16 12:15:00.000 |
| 2019-07-16 12:21:00.000 | 2019-07-16 12:30:00.000 |
| 2019-07-16 12:29:00.000 | 2019-07-16 12:30:00.000 |
| 2019-07-16 12:35:00.000 | 2019-07-16 12:30:00.000 |
| 2019-07-16 12:38:00.000 | 2019-07-16 12:45:00.000 |
| 2019-07-16 12:56:00.000 | 2019-07-16 13:00:00.000 |
+-------------------------+-------------------------+