【发布时间】:2018-06-17 17:01:29
【问题描述】:
我正在尝试在存储过程中执行准备好的语句。
但我遇到了问题。
这是存储过程:
DELIMITER $$
CREATE DEFINER=`root`@`localhost` PROCEDURE `getAllUserLunchReport`(IN `start_date` DATETIME, IN `end_date` DATETIME)
BEGIN
SET GLOBAL group_concat_max_len=4294967295;
SET @SQL = NULL;
SET @start_date = DATE(start_date);
SET @end_date = DATE(end_date);
SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'SUM(CASE WHEN date = "',DATE(issuedDateTime),'" THEN lunchStatus ELSE 0 END) AS `',DATE(issuedDateTime),'`'
)
) INTO @SQL
FROM `lunch_status`
WHERE DATE(issuedDateTime) BETWEEN @start_date AND @end_date;
SET @SQL
= CONCAT('SELECT userId, ', @SQL, '
FROM
(
SELECT userId, lunchStatus, DATE(issuedDateTime) as date
FROM `lunch_status`
WHERE DATE(issuedDateTime) BETWEEN "',@start_date,'" AND "',@end_date,'"
) as a
GROUP BY userId;');
PREPARE stmt FROM @SQL;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
END$$
DELIMITER ;
这是错误:
PDOStatement: You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'NULL' at line 1
这是控制器:
public function weeklyLunchReport($date1=null, $date2=null)
{
$user = AclHelper::getCurrentUser();
$default_userID = intval($user['user_id']);
$defDate = new DateTime();
$default_date = $defDate->format('Y-m-d');
$date1 = (isset($date1) && $date1 != '') ? $date1 : $default_date;
$date2 = (isset($date2) && $date2 != '') ? $date2 : $default_date;
$records = $this->db->exec("CALL getAllUserLunchReport ('$date1','$date2')");
return $records;
}
另外: 这是 SQL 变量的值:
SELECT userId,
SUM(CASE WHEN date = "2018-06-03" THEN lunchStatus ELSE 0 END) AS `2018-06-03`,
SUM(CASE WHEN date = "2018-06-04" THEN lunchStatus ELSE 0 END) AS `2018-06-04`,
SUM(CASE WHEN date = "2018-06-06" THEN lunchStatus ELSE 0 END) AS `2018-06-06`,
SUM(CASE WHEN date = "2018-06-07" THEN lunchStatus ELSE 0 END) AS `2018-06-07`,
SUM(CASE WHEN date = "2018-06-08" THEN lunchStatus ELSE 0 END) AS `2018-06-08`
FROM
(
SELECT userId, lunchStatus, DATE(issuedDateTime) as date
FROM `lunch_status`
WHERE DATE(issuedDateTime) BETWEEN "2018-06-03" AND "2018-06-09"
) as a
GROUP BY userId;
单独运行此查询字符串会给出预期的结果集。
查询似乎一切正常,但我不知道哪里出错了。
非常感谢任何帮助。提前致谢。
【问题讨论】:
-
在您尝试准备之前,我会输出您的
@SQL字符串的最终状态。当您不查看代码时,很难调试代码,但是您正在查看不同的代码,这些代码应该会生成您需要调试的代码。一旦你看到@SQL的最终值,我敢打赌这个错误会变得更清楚。 -
@BillKarwin 我已经更新了
@SQL变量值字符串。单独执行生成的查询字符串给出了预期的结果集。
标签: php mysql stored-procedures prepared-statement