如何从 flatpickr 获取日期输入？

Question

我正在将我的 jquery ui datepicker 更改为 flatpickr。但我需要知道如何为 flatpickr 做到这一点$('#from2').datepicker('getDate')。我在网上找不到如何使用 flatpickr 进行操作。

感谢您的宝贵时间。

*编辑

function getDays() {
    let start = $('#from1').datepicker('getDate'),
        end   = $('#to1').datepicker('getDate'),
        days  = (end - start) / 1000 / 60 / 60 / 24;
        if(days == 0 || days > 0) {
    $('#howManyNights').val(days);
  }
    return days;
}

*不适用于 flatpickr：

function getDays() {
    let start = $('#from1').val();
        end   = $('#to1').val();
        days  = (end - start) / 1000 / 60 / 60 / 24;
        console.log(days);
        if(days == 0 || days > 0) {
    $('#howManyNights').val(days);
    }
    return days;
}

天 = 南

Answer 1

像这样尝试，通过使用 flatpickr 的值制作日期对象（您可以运行的工作 sn-p）

var from1 = flatpickr('#from1', {});
var to1 = flatpickr('#to1', {});

function getDays() {
    var start = new Date($('#from1').val());
    var end   = new Date($('#to1').val());
    days  = (end - start) / 1000 / 60 / 60 / 24;
    if(days == 0 || days > 0) {
      $('#howManyNights').val(days);
    }
    return days;
}

<script src="https://cdnjs.cloudflare.com/ajax/libs/flatpickr/4.6.3/flatpickr.js"></script>
<link href="https://cdnjs.cloudflare.com/ajax/libs/flatpickr/4.6.3/flatpickr.css" rel="stylesheet"/>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/2.2.4/jquery.min.js"></script>

From:<input name="from1" id="from1" type="text">
To:<input name="to1" id="to1" type="text">
How Many:<input name="howManyNights" id="howManyNights" type="text">
<button onclick="getDays()">Get Days</button>