如果多个准备好的语句之一失败，则停止并恢复答案

【问题标题】：Stop and revert if one of multiple prepared statements fail如果多个准备好的语句之一失败，则停止并恢复
【发布时间】：2016-04-18 15:33:11
【问题描述】：

我有一个类数据库，它有多种方法，一些执行准备好的语句以在我的表中创建新行。目前，一切正常，但如果出现问题，有没有办法停止进一步的查询并恢复之前的查询。

这只是我的表单当前处理方式的一个小例子：

if(isset($_POST["someSubmitName"]) : 
//post variables 
....
// Start Queries 
$db->address_table_insert_statement($firstName, $lastName, $companyName, $streetAddress, $streetAddress2, $streetAddress3, $city, $state, $zip, $country, $phone, $fax, $email, $date, $date);
$addressId = mysqli_insert_id($db->connection);
$db->address_table_insert_statement($firstName, $lastName, $companyName, $billingStreetAddress, $billingStreetAddress2, $billingStreetAddress3, $billingCity, $billingState, $billingZipCode, $billingCountry, $billingPhone, $billingFax, $billingEmail, $date, $date);
$billingAdressId = mysqli_insert_id($db->connection);
$db->account_table_insert_statement($active, $addressId, $billingAddressId, $dateCreated, $dateModified);
endif;

同样，如果这 3 个中的任何一个失败，我想恢复所有查询并退出此表单处理。谢谢！

【问题讨论】：

标签： php mysql mysqli

【解决方案1】：

通过在 mysqli 连接之前添加此行将 mysqli 置于异常模式
```
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
```
将您的查询封装在一个事务中
将事务包装在 try..catch 语句中，并在其中添加回滚调用。

所以代码会是这样的

mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$db = new mysqli(...);
...
try {
    $db->autocommit(FALSE);

    $db->address_table_insert_statement($firstName, $lastName, $companyName, $streetAddress, $streetAddress2, $streetAddress3, $city, $state, $zip, $country, $phone, $fax, $email, $date, $date);
    $addressId = mysqli_insert_id($db->connection);
    $db->address_table_insert_statement($firstName, $lastName, $companyName, $billingStreetAddress, $billingStreetAddress2, $billingStreetAddress3, $billingCity, $billingState, $billingZipCode, $billingCountry, $billingPhone, $billingFax, $billingEmail, $date, $date);
    $billingAdressId = mysqli_insert_id($db->connection);
    $db->account_table_insert_statement($active, $addressId, $billingAddressId, $dateCreated, $dateModified);

    $db->commit();
} catch (\Exception $e) {
    $db->rollback();
    throw $e;
}

【讨论】：