PHP 没有发布到 MYSQL

Question

我一定忽略了一些非常明显的东西，但是我已经检查了我所有的 PHP 代码，并将其与其他有效的形式进行了比较。我找不到任何差异。基本上，当我提交此表单时，它不会在我的数据库中的 cmets 表中添加任何内容。一定有一些非常明显的东西我忽略了。你能帮我弄清楚我错过了什么吗？这是我的php表单：

<?php
session_start();
require_once('functions/functions.php');

echo do_html(array('title'=>'Comments', 'css_file'=>'assets/css/style.css'));
echo do_header();
?>

<div id="usernameDiv"><?php echo do_greetings(); ?></div> 
<div>
    <p class="lead">We are always looking for new feedback, whether you have registered or not! Please leave your name and email address. Thank you!</p>
</div>

<form action="actions/comments.php" method="post">

    First Name:<br>
    <input type="text" name="fname">
    <br>
    Last Name:<br>
    <input type="text" name="lname">
    <br>
    Email Address:<br>
    <input type="text" name="eaddress"> <br><br> 

    <textarea name="ucomment" cols="50" rows="7" placeholder="Enter comments here..."></textarea>

    <br><br>
    <input type="submit" name="submitButton" value="Submit" >

</form>

<?php echo do_footer(); ?>

然后，这里是处理它到表单的php文件。

<?php
require_once("constants.php"); 

$link = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME);
mysqli_set_charset($link, 'utf8');
if (!$link) {
    die("Database connection failed: " . mysqli_error($link));
}
if (isset($_POST['fname'])) {

    $post_vars = array('fname', 'lname', 'eaddress', 'ucomment');
    foreach($post_vars as $key) {
        $$key = mysqli_real_escape_string($link, $_POST[$key]);

    }

    $sql = "INSERT INTO comments (fname, lname, eaddress, ucomment) VALUES ('$fname', '$lname', '$eaddress', '$ucomment');";
    $result = mysqli_query($link, $sql);
}
mysqli_close($link);
?>

另外，这是我的常量文件，但我怀疑它在这里，因为我的其他表单都可以正常发布：

<?php
//This is constants.php file
define('DB_HOST', 'localhost');
define('DB_USER', 'root');
define('DB_PASSWORD', 'password');
define('DB_NAME', 'conference');
?>

Answer 1

添加更多错误处理....

<?php
if ( !isset($_POST['fname']) ) {
    echo '...';
}
else {
    require_once "constants.php";

    $link = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME);
    if ($link->connect_errno) {
        trigger_error( sprintf('mysqli connect error (%d) %s', $link->connect_errno, $link->connect_error), E_USER_ERROR);
        die;
    }
    else if ( !mysqli_set_charset($link, 'utf8') ) {
        trigger_error('Error loading character set utf8: '. $link->error, E_USER_ERROR);
    }
    else {
        $post_vars = array('fname', 'lname', 'eaddress', 'ucomment');
        foreach($post_vars as $key) {
            if ( !isset($_POST[$key]) ) {
                trigger_error('missing POST parameter '.$key, E_USER_ERROR);
                // ....and some bailout code here
            }
            $$key = mysqli_real_escape_string($link, $_POST[$key]);
        }
        $sql = "INSERT INTO comments (fname, lname, eaddress, ucomment) VALUES ('$fname', '$lname', '$eaddress', '$ucomment')";
        $result = mysqli_query($link, $sql);
        if ( !$result ) {
            trigger_error('query failed. '. $link->error, E_USER_ERROR);
        }
        else {
            echo $link->affected_rows, ' record(s) inserted';
        }
    }
    mysqli_close($link);
}