【发布时间】:2014-04-04 09:07:09
【问题描述】:
正在处理一个项目,我将从我的数据库中提取并在表单选择中显示池名称。但非常不确定如何比这更进一步。
$con=mysqli_connect("localhost","root","","nih_bw");
// Check connection
if (mysqli_connect_errno($con))
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$sql = "Select name from pools";
if(!$result = $db->query($sql)){
die('There was an error running the query [' . $db->error . ']');
}
mysqli_close($con);
【问题讨论】:
-
代码不完整。
mysqli_close()之前缺少右括号 -
您可以尝试一些教程或至少其他类别的问题。以The very recent one 为例