从 url 请求解析 php 中的 json 数据答案

【问题标题】：parsing json data in php from a url request从 url 请求解析 php 中的 json 数据
【发布时间】：2018-02-01 13:29:10
【问题描述】：

尝试解析以下数据，但无法获取正确的项目来回显。我做错了什么？

{  
    "total_results":12585,
    "organizations":[  
      {  
         "ein":232669352,
         "strein":"23-2669352",
         "name":"AMERICAN HOME LIFE INTERNATIONAL INC",
         "sub_name":"AMERICAN HOME LIFE INTERNATIONAL INC",
         "city":"LANCASTER",
         "state":"PA",
         "ntee_code":"Q220",
         "raw_ntee_code":"Q220",
         "subseccd":3,
         "has_subseccd":true,
         "have_filings":true,
         "have_extracts":true,
         "have_pdfs":true,
         "score":417.01215
      },
      {  
         "ein":251691788,
         "strein":"25-1691788",
         "name":"HOME LIFE MINISTRIES",
         "sub_name":"HOME LIFE MINISTRIES",
         "city":"ANNVILLE",
         "state":"PA",
         "ntee_code":"X20",
         "raw_ntee_code":"X20",
         "subseccd":3,
         "has_subseccd":true,
         "have_filings":true,
         "have_extracts":true,
         "have_pdfs":true,
         "score":147.28578
      },
      {  
         "ein":240782824,
         "strein":"24-0782824",
         "name":"MIFFLINBURG AMERICAN LEGION HOME ASSOCIATION INC",
         "sub_name":"MIFFLINBURG AMERICAN LEGION HOME ASSOCIATION INC",
         "city":"MIFFLINBURG",
         "state":"PA",
         "ntee_code":null,
         "raw_ntee_code":null,
         "subseccd":7,
         "has_subseccd":true,
         "have_filings":true,
         "have_extracts":true,
         "have_pdfs":true,
         "score":145.12933
      },

这是我目前所拥有的代码：

<?php
    $url = "https://projects.propublica.org/nonprofits/api/v2/search.json?
    q=%22american%20home%20life%20international%20inc%22&state%5Bid%5D=PA";
    $json = file_get_contents($url);
    $json_data = json_decode($json, true);
    foreach ($json['organizations'] as $address)
    {
        echo "items:". $address['ein'] ."\n";
    };
?>

【问题讨论】：

请阅读how to ask good questions。 “有麻烦”太宽泛了，也格式化json样例。
您正在尝试遍历字符串，而不是 $json_data 变量。注意 PHP 提出的警告 - 它试图帮助你。
foreach ($json_data['organizations'] as $address)
如果对您有帮助，请选择答案

标签： php arrays json parsing

【解决方案1】：

改变

foreach ($json['organizations'] as $address)

到

foreach ($json_data['organizations'] as $address)

【讨论】：