在codeigniter查询中转换mysql查询答案

【问题标题】：convert mysql query in codeigniter query在codeigniter查询中转换mysql查询
【发布时间】：2013-09-30 06:16:08
【问题描述】：

将mysql查询转换为codeigniter查询

当前查询：

$query = "SELECT a.*, b.cost AS future_cost, b.start_date AS future_date
          FROM (
            SELECT * FROM (
              SELECT * FROM outbound_routes 
              ORDER BY start_date
            ) x 
          GROUP BY pattern
          ) a
          LEFT JOIN (
            SELECT * FROM outbound_routes 
            ORDER BY start_date
          ) b 
          ON a.pattern = b.pattern AND a.id != b.id
          GROUP BY a.pattern";

$result=$this->db->query($query);

在粗体查询中，我想附加搜索变量，例如

 $this->db->where('pattern','1');

我们将不胜感激任何帮助和想法。

【问题讨论】：

我认为您不能使用活动记录类来连接两个 SQL 查询。您必须使用$this->db-query('ALL YOUR SQL HERE') 方法。

标签： php mysql sql codeigniter

【解决方案1】：

试试这个

$this->db->select('select a.*, b.cost AS future_cost, b.start_date AS future_date');
$this->db->from('(select * from   (select * from outbound_routes order by start_date) x group by pattern) a');
$this->db->join('(select * from outbound_routes order by start_date) b', 'a.pattern = b.pattern and a.id != b.id','left ');
$this->db->where('a.pattern','1');
$this->db->group_by("a.pattern"); 
$result=$query = $this->db->get();

Active Record

或查看CodeIgniter Subqueries

【讨论】：

【解决方案2】：

不幸的是，我认为不可能使用 codeigniters active record class 将 where 子句附加到现有 SQL 中。活动记录类只能处理表之间的简单连接。

要将其附加到现有查询，您可以使用查询绑定将变量传递给查询。

$query = "SELECT a.*, b.cost AS future_cost, b.start_date AS future_date
          FROM (
            SELECT * FROM (
              SELECT * FROM outbound_routes 
              ORDER BY start_date
            ) x 
          GROUP BY pattern
          ) a
          LEFT JOIN (
            SELECT * FROM outbound_routes 
            ORDER BY start_date
          ) b 
          ON a.pattern = b.pattern AND a.id != b.id
          GROUP BY a.pattern
          WHERE pattern = ?";

$result = $this->db->query($query, array(1));

【讨论】：