带有联接 4 表的 Codeigniter 活动记录

Question

伙计们，我有 4 张桌子 uhd_voucher_menu、uhd_menu、uhd_voucher_variant_menu、uhd_variant_menu

其中uhd_voucher_menu和uhd_menu通过menu_id连接，比uhd_voucher_variant_menu和uhd_voucher_menu通过voucher_menu_id连接，最后一个uhd_variant_menu和voucher_variant_menu通过variant_menu_id连接

这是我获取数据的代码：

        $this->db->select("uhd_voucher_menu.voucher_id,uhd_menu.menu_name,uhd_voucher_menu.qty,uhd_variant_menu.variant_name,uhd_voucher_menu.voucher_menu_id");
        $this->db->from("uhd_voucher_menu");
        $this->db->join("uhd_menu","uhd_menu.menu_id = uhd_voucher_menu.menu_id");
        $this->db->join("uhd_voucher_variant_menu","uhd_voucher_variant_menu.voucher_menu_id = uhd_voucher_menu.voucher_menu_id","left");
        $this->db->join("uhd_variant_menu","uhd_variant_menu.variant_menu_id = uhd_voucher_variant_menu.variant_menu_id","left");
        $this->db->where("voucher_id",$data["voucher"]["voucher_id"]);
        $this->db->where("uhd_menu.restaurant_id",$restaurant_id);
        $res = $this->db->get()->result_array();

从该活动记录中将返回此数据：

[0]=>
array(5) {
  ["voucher_id"]=>
  string(1) "1"
  ["menu_name"]=>
  string(13) "Golden Salmon"
  ["qty"]=>
  string(1) "2"
  ["variant_name"]=>
  string(5) "Spicy"
  ["voucher_menu_id"]=>
  string(1) "3"
}
[1]=>
array(5) {
  ["voucher_id"]=>
  string(1) "1"
  ["menu_name"]=>
  string(13) "Golden Salmon"
  ["qty"]=>
  string(1) "2"
  ["variant_name"]=>
  string(6) "Medium"
  ["voucher_menu_id"]=>
  string(1) "3"
}
[2]=>
array(5) {
  ["voucher_id"]=>
  string(1) "1"
  ["menu_name"]=>
  string(13) "Golden Salmon"
  ["qty"]=>
  string(1) "1"
  ["variant_name"]=>
  string(4) "Sour"
  ["voucher_menu_id"]=>
  string(1) "4"
}
[3]=>
array(5) {
  ["voucher_id"]=>
  string(1) "1"
  ["menu_name"]=>
  string(13) "Golden Salmon"
  ["qty"]=>
  string(1) "1"
  ["variant_name"]=>
  string(6) "Medium"
  ["voucher_menu_id"]=>
  string(1) "4"
}
[4]=>
array(5) {
  ["voucher_id"]=>
  string(1) "1"
  ["menu_name"]=>
  string(14) "Red Crown Crab"
  ["qty"]=>
  string(1) "2"
  ["variant_name"]=>
  NULL
  ["voucher_menu_id"]=>
  string(1) "1"
}
[5]=>
array(5) {
  ["voucher_id"]=>
  string(1) "1"
  ["menu_name"]=>
  string(8) "Omellete"
  ["qty"]=>
  string(1) "3"
  ["variant_name"]=>
  NULL
  ["voucher_menu_id"]=>
  string(1) "2"
}

如您所见，golden_salmon 与 voucher_menu_id 相同，返回两次

我想要voucher_menu_id 是否相同，所以从这个数据：

[0]=>
array(5) {
  ["voucher_id"]=>
  string(1) "1"
  ["menu_name"]=>
  string(13) "Golden Salmon"
  ["qty"]=>
  string(1) "2"
  ["variant_name"]=>
  string(5) "Spicy"
  ["voucher_menu_id"]=>
  string(1) "3"
}
[1]=>
array(5) {
  ["voucher_id"]=>
  string(1) "1"
  ["menu_name"]=>
  string(13) "Golden Salmon"
  ["qty"]=>
  string(1) "2"
  ["variant_name"]=>
  string(6) "Medium"
  ["voucher_menu_id"]=>
  string(1) "3"
}

我希望数据返回变成这样：

[0]=>
array(5) {
  ["voucher_id"]=>
  string(1) "1"
  ["menu_name"]=>
  string(13) "Golden Salmon"
  ["qty"]=>
  string(1) "2"
  ["variant_name"]=>
  array(2){
    [1]=>
    string(5) "Spicy"
    [2]=>
    string(6) "Medium"
  }
  ["voucher_menu_id"]=>
  string(1) "3"
}

与另一个 golden_salmon 相同，voucher_menu_id 4

我希望variant_name 变成数组，这样voucher_menu_id 相同的 if 数据就不会调用两次

你们能帮我如何按照我的意愿执行数据​​吗？ 谢谢（：

Answer 1

你必须使用group by，我稍微修改了你的查询：

 $this->db->select("uhd_voucher_menu.voucher_id,uhd_menu.menu_name,uhd_voucher_menu.qty,GROUP_CONCAT(uhd_variant_menu.variant_name SEPARATOR ',') AS variants,uhd_voucher_menu.voucher_menu_id");
    $this->db->from("uhd_voucher_menu");
    $this->db->join("uhd_menu","uhd_menu.menu_id = uhd_voucher_menu.menu_id");
    $this->db->join("uhd_voucher_variant_menu","uhd_voucher_variant_menu.voucher_menu_id = uhd_voucher_menu.voucher_menu_id","left");
    $this->db->join("uhd_variant_menu","uhd_variant_menu.variant_menu_id = uhd_voucher_variant_menu.variant_menu_id","left");
    $this->db->where("voucher_id",$data["voucher"]["voucher_id"]);
    $this->db->where("uhd_menu.restaurant_id",$restaurant_id);
$this->db->group_by("uhd_voucher_menu.voucher_id");
    $res = $this->db->get()->result_array();

查询输出后，我们可以将逗号分隔的值转换为数组。

尝试发布结果...