【问题标题】:Upload img path to db codeigniter将图像路径上传到 db codeigniter
【发布时间】:2013-02-03 19:29:59
【问题描述】:

我正在尝试上传已上传图片的路径。

当我在底部注释掉模型时,表单当前将文件发送到文件系统没有问题。

控制器:

<?php if ( ! defined('BASEPATH')) exit('No direct script access allowed');

class Upload extends CI_Controller {
    function __construct(){
        parent::__construct();
        $this->load->helper(array('form', 'url'));
    }

    function index() {
        $this->load->view('uploaderview', array('error' => ' ' ));
    }

    function do_upload(){
        $config['upload_path'] = './upl0d/';
        $config['allowed_types'] = 'gif|jpg|png';
        $config['max_size'] = '2048';      //2mb
        $config['max_width']  = '1024';
        $config['max_height']  = '768';
        $config['encrypt_name'] = FALSE;
        $this->load->library('upload', $config);

        if ( ! $this->upload->do_upload()) {
            $error = array('error' => $this->upload->display_errors());
            $this->load->view('uploaderview', $error);
        } else {
            ## Insert into filesystem.
            $data = array('upload_data' => $this->upload->data());
            ## load the success page.
            $this->load->view('uploadsuccess', $data);
            ## Insert into db
            ## then insert the img name into the database
            this->load->model('uploadermodel');
            $this->uploadermodel->uploadcoupon();               
        }
    }
}

还有一个模型:

<?php
class Uploadermodel extends CI_Model{
    function __construct(){
        // Call the Model constructor
        parent::__construct();
    }

    function uploadcoupon(){
        $uploadFileName = $upload_data['orig_name'];
        $currentDt = date('Y-m-d H:i:s');
        $data = array('fileNameUploaded'=>$uploadFileName,'date'=>$currentDt);
        $this->db->insert('Coupon', $data); 
    }
}   
?>

当我包含模型时,我收到以下错误:

syntax error, unexpected T_OBJECT_OPERATOR on line 36

这是控制器的第 36 行:

this->load->model('uploadermodel');

有人看到我在这里做错了吗?

【问题讨论】:

  • 我真傻。谢谢佩卡
  • 问题是变量 $uploadFileName 为 null 或为空。我该如何解决这个问题?
  • $upload_data 应该来自哪里?您没有从其他函数传递它
  • 如果您查看:ellislab.com/codeigniter/user-guide/libraries/… 它在那里使用它。应该传入哪个函数

标签: php codeigniter file-upload


【解决方案1】:

@CodeTalk - 查看您的其他问题以获得更完整的详细信息:

Pass Data from Controller to Model Codeigniter

但是你需要通过

 $this->uploadermodel->uploadcoupon($my_insert_data); 

又一次:

uploadcoupon($my_insert_data)

【讨论】:

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