【发布时间】:2019-03-03 18:52:09
【问题描述】:
如何在继续注册到结构之前检查表中是否存在字符名称、表>字符>字符 老字号
【问题讨论】:
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我想让它检查是否有人已经存在使用相同的名字,它不允许在表中注册
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请向我们展示您的型号代码,以便我们为您提供帮助
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好吧,我的模态是
标签: php codeigniter email
如何在继续注册到结构之前检查表中是否存在字符名称、表>字符>字符 老字号
【问题讨论】:
标签: php codeigniter email
在插入新记录之前检查数据库中的名称
$data = array(
"id_username" => $this->session->id_account,
"name_character" => $nome,
"birthdate" => $data,
"origin" => $origem,
"gender" => $sexo,
"pergunta1" => $pergunta3,
"pergunta2" => $pergunta4,
"history" => $history
);
$if_exists = $this->usuarios_model->check_user($data['name_character']);
//Here apply condition to check if user is exists or not
if($if_exists > 0){
//Already Exists
}else{
$this->usuarios_model->criarPersonagem($data); //New registration
}
型号
public function check_user($name_character){
//Here, get the number if rows with the new user name
return $this->db->get_where('characters', ['Character' => $name_character])->num_rows();
}
【讨论】:
curly bracket。
characters WHERE name_character = 'pedro_henrique'
name_character。确保此处的名称正确['name_character' => $name_character]
控制者:
$flag = $this->usuarios_model->criarPersonagem($data);
if($flag == 1){
redirect("painel/sucesso"); // lembrar de criar a mensagem sucesso!
}else{
redirect("painel/fracasso"); // lembrar de criar a mensagem fracasso!
}
型号:
function criarPersonagem($data){
$query = $this->db->get_where('characters',array('name_character'=>$data['name_character']));
if ($query->num_rows() > 0) {
return 0;
}else{
//register code
return 1;
}
}
【讨论】: