试图获取非对象的属性“密码”，异常：“ErrorException”答案

【问题标题】：Trying to get property 'password' of non-object", exception: "ErrorException"试图获取非对象的属性“密码”，异常：“ErrorException”
【发布时间】：2020-11-03 07:30:08
【问题描述】：

 Laravel change password thrown with the  message of Trying to get property 'password' of non-object", exception:

如何解决message: Trying to get property 'password' of non-object"，异常： “ErrorException”请帮助..................................................

 public function updateAuthUserPassword(Request $request)
 {
    $this->validate($request, [
        'current' => 'required',
        'newpassword' => 'required',
        'password_confirmation' => 'required|same:newpassword'
    ]);

    $user = User::find(Auth::id());

    if (!Hash::check($request->current, $user->password)) {
        return response()->json(['errors' => ['current'=> ['Current password does not match']]], 
    422);
    }

    $user->password = Hash::make($request->newpassword);
    $user->save();

    return $user;
    }

【问题讨论】：

确保 $user 不为空

标签： laravel vue.js

【解决方案1】：

改变

$user = User::find(Auth::id());

到

$user = User::findOrFail(Auth::id());

findOrFail 将接受一个 id 并返回一个模型。如果不存在匹配的模型，则抛出 ModelNotFoundException。您也可以使用 try catch 块捕获异常。

所以你可以把你的完整代码写成

public function updateAuthUserPassword(Request $request)
 {
try{
   .... other codes
   $user = User::findOrFail(Auth::id());
}catch(ModelNotFoundException $e){
    // return with message that no user found.
}

【讨论】：